Four million two hundred fifty thousand
If we have
y = 6x + 1 and x - y = 11, we can take advantage of y - y = 0 as follows:
Subtract x from both sides of the 2nd equation:
-y = 11 - x
Now combine
y = 6x + 1
-y = 11 - x
--------------
0 = 5x + 12. Solving for x, x = -12/5. Using the equation above, find y:
-y = 11 - x
= 11 - (-12/5)
= 55/5 + 12/5 = 67/5
Then the solution is (-12.5, 67/5).
We have that
x²<span>-20x
</span><span>Group
terms that contain the same variable
</span>(x²-20x)
Complete
the square
(x²-20x+10²)------> (x-10)²
the answer is
the number must be 100
Answer:
The fourth option is the correct answer
Step-by-step explanation:
The given expression is
-2n(5+n-8-3n)
Given that n=3,We substitute the value of n into the expression and simplify.
This implies that,
-2n(5+n-8-3n)=-2(3)[5+3-8-3(3)]
=-6(5+3-8-9)
=-6(-9)
=54
Hence the answer is 54
