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IRISSAK [1]
3 years ago
6

Simplify 400-[200+35-70(100/25)}] hurry plz

Mathematics
2 answers:
tresset_1 [31]3 years ago
6 0

Answer:

445

Step-by-step explanation:

400 - [200 + 35 - 70 (100/25)]

400 - [200 + 35 - 70 (4)]

400 - [200 + 35 - 280]

400 - [200 - 245]

400 - [- 45]

400 + 45

445

If you have any questions, let me know! hope this helps!

larisa [96]3 years ago
3 0

Answer:

445

Step-by-step explanation:

don't know if right sorry if not

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inna [77]

Answer:

y = 4

Step-by-step explanation:

6y + 30 = 54

subtract 30 from each side

6y = 24

divide each side by 6

y = 4

7 0
3 years ago
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I don’t know how to do question 3
antoniya [11.8K]

Answer:

The function y = -x whose reflection in the line y =x is itself.

Step-by-step explanation:

A reflection that maps every point of a figure to an image across a fixed line. Then the fixed line is called the line of reflection.

The reflection of the point (x,y)  in the line y = x is the point (y, x).

Therefore, the  function y = -x  whose  reflection in the line y =x is itself.

Symmetries of the function f(x)= -x is:    

A function symmetric with respect to the y-axis is called an even function.

If f(-x) = f(x)

A function that is symmetric with respect to the origin is called an odd function.

if f(-x) = -f(x)

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this function is symmetrical to with respect to origin.

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5 0
3 years ago
All the given quadrilaterals in the picture on the right are squares and #1 ≅ #3, #2 ≅ # 4. find the area of the shaded region,
Anika [276]

Answer:

Step-by-step explanation:

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If the big square has a area of 900, this implies that its side is \sqrt{900}, so the two diagonal of squares 2 and 4 added together would be \sqrt{900}, therefore one diagonal wold be \frac{\sqrt{900}}{2}. and its side \frac{\sqrt{900}}{2}\frac{1}{\sqrt{2}}. The area (of one square) is (\frac{\sqrt{900}}{2}\frac{1}{\sqrt{2}})^2=\frac{225}{2}

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6 0
3 years ago
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Keith_Richards [23]

Answer:

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Step-by-step explanation:

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Plugging in x=7 into 9x+21:

\widehat{DG}=9(7)+21,\\\widehat{DG}=63+21,\\\widehat{DG}=\boxed{84^{\circ}}

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