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3 years ago

Can some one help me plzzz will give brainiest

Mathematics

1 answer:

tino4ka555 [31]3 years ago

7 0

Answer:

3rd choice Hoped this helped :_)

Step-by-step explanation:

Brainliest plz ^

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Please help....

yanalaym [24]

Answer:

Starting average customer rating was 5.

Step-by-step explanation:

Equation representing the average customer rating at Austin's bakery over time is,

y = 0.25x + 5

Here, 'x' represents the time or duration.

Starting average customer rating means value of y at x = 0.

Therefore, y = 0.25(0) + 5

y = 5

Starting average customer rating was 5.

4 0

3 years ago

The low temperatures for four nights in December for a city are recorded below.

photoshop1234 [79]

Answer:

the answer is <u>A</u><u> </u>

Step-by-step explanation:

its because -4 is the coldest and 3 is the warmest out of the rest

5 0

3 years ago

Parallelogram MNPQ was dilated to create parallelogram M'N'P'Q'. On a coordinate plane, 2 parallelograms are shown. Parallelogra

Naddika [18.5K]

Answer:

The answer is below

Step-by-step explanation:

Which statements are true about the parallelograms? Check all that apply.

The length of side MN is 2 units.

The length of side M'N' is 5 units.

The image is smaller than the pre-image.

Sides MQ and M'Q' both have the same slope, 1.

The scale factor is 2/5

a) The length of side MN is determined using the formula:

$|MN|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(4-2)^2+(-2-(-2))^2}=\sqrt{2^2}=2\\ \\ |MN|=2$

The first option is correct

b) The length of side M'N' is determined using the formula:

$|M'N'|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(10-5)^2+(-5-(-5))^2}=\sqrt{5^2}=2\\ \\ |M'N'|=5$

The second option is correct

c) From the coordinates of parallelogram MNPQ and M'N'P'Q', we can see that parallelogram MNPQ is dilated by a factor of 5/2 to produce parallelogram M'N'P'Q' , hence parallelogram M'N'P'Q' is bigger that parallelogram MNPQ. This means that The image is bigger than the pre-image.

The third option is wrong

d) The slopes are given as:

$Slope\ of\ MQ=\frac{Change\ in\ y}{Change\ in\ x}=\frac{1-2}{-3-(-2)} =1\\ \\Slope\ of\ M'Q'=\frac{Change\ in\ y}{Change\ in\ x}=\frac{3-5}{-7-(-5)} =1\\$

Option four is correct

e) From the coordinates of parallelogram MNPQ and M'N'P'Q', we can see that parallelogram MNPQ is dilated by a factor of 5/2 to produce parallelogram M'N'P'Q', hence the scale factor is 5/2

Option 5 is wrong

6 0

3 years ago

Read 2 more answers

Is 1/sec^2(θ) the same as cos^2(θ)

dexar [7]

$\frac{1}{sec^2\theta}=cos^2\theta\\\\L=\frac{1}{\left(\frac{1}{cos\theta}\right)^2}=\frac{1}{\frac{1}{cos^2\theta}}=1:\frac{1}{cos^2\theta}=1\cdot\frac{cos^2\theta}{1}=cos^2\theta=R$

8 0

3 years ago

All points of the step function f(x) are graphed.

mrs_skeptik [129]

Answer:

On a coordinate plane, a step graph has horizontal segments that are each 1 unit long. The left end of each segment is a closed circle. The right end of each segment is an open circle. The left-most segment goes from (negative 5, 3) to (negative 4, 3). Each segment is 1 unit lower and 1 unit farther to the right than the previous segment. The right-most segment goes from (2, negative 4) to (3, negative 4).

Step-by-step explanation:

8 0

3 years ago