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3 years ago

The difference of y and 8.1 is 20. Flnd the value of y.

Mathematics

1 answer:

White raven [17]3 years ago

5 0

Answer:

y = 28.1

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Step-by-step explanation:

Step 1: Set Up Equation

"Difference" is subtraction

"y" is y

"8.1" is 8.1

"is" is equal

"20" is 20

y - 8.1 = 20

Step 2: Solve for y

Add 8.1 to both sides: y = 28.1

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Given the set of ordered pairs: {(1,3), (2,7), (x,5), (6,4)}.

MrMuchimi

Answer:

Step-by-step explanation:

2 is a value of x that would not make the set a function because a function can't have multiple coordinates wit hthe same domain (x-coordinate). 2 is a domain that has already been used in the point (2,7). If this is used in (x,5), the point would become (2,5) and repeat a domain.

Note:

The x-coordinate could also be 1 or 6 because they have been used as domains as well.

Hope it helps!

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2 years ago

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liq [111]

Answer:

that is an addition sign the correct answer is B

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago

A composite figure is comprised of a square and 4 semicircles. How can you decompose the composite figure to determine its area?

tangare [24]

Answer:

As a square and four semi circles

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The sum of two consecutive even integers is 66. Find the numbers.

evablogger [386]

Let the consecutive even numbers be n and n+2.
From given condition,
n + n+2 = 66
2n = 64
∴ n = 32.
Therefore, the two consecutive even numbers are.
n = 32 and n+2 = 34.

4 0

3 years ago