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bonufazy [111]
3 years ago
15

Find an equation of the line with the given y-intercept and slope m.

Mathematics
1 answer:
Alenkasestr [34]3 years ago
5 0

Answer:

y=4.2x-3.7

Step-by-step explanation:

Slope-intercept form is y=mx+b, so just plug in the numbers to where they go in the formula.

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Danny charges $40 for 4 hours of swimming lessons, Martin charges $85 for 5 hours of swimming lessons. Who offers a better deal?
Ratling [72]

Answer:

Danny does

Step-by-step explanation: 40 / 4 = 10

                                              85 / 5 = 17

10 is less than 17 meaning that Danny is offering a better deal.

Hope this helps!

4 0
3 years ago
Read 2 more answers
You move down 6 units and left 9 units. You end at (-5, -3). Where did you start?
Olegator [25]
(4, 3) i think lol goodluck
6 0
3 years ago
Which complex number has an absolute value of 5?<br> -3 + 4i<br> 2 +3i<br> 7-2i<br> 9 +4i
fiasKO [112]

Answer:

-3+4i

Step-by-step explanation:

on a graph the complex number is (-3,4) The magnitude is -3^2+4^2=c^2

c=5 when solved

6 0
3 years ago
Read 2 more answers
According to an​ almanac, 60​% of adult smokers started smoking before turning 18 years old. ​(a) compute the mean and standard
larisa [96]
The given problem describes a binomial distribution with p = 60% = 0.6. Given that there are 400 trials, i.e. n = 400.

a.) The mean is given by:

\mu=np=400\times0.6=240

The standard deviation is given by:

\sigma=\sqrt{npq} \\  \\ =\sqrt{np(1-p)} \\  \\ =\sqrt{400(0.6)(0.4)} \\  \\ =\sqrt{96}=9.80


b.)  The mean means that in an experiment of 400 adult smokers, we expect on the average to get about 240 smokers who started smoking before turning 18 years.


c.) It would be unusual to observe <span>340 smokers who started smoking before turning 18 years old in a random sample of 400 adult​ smokers because 340 is far greater than the mean of the distribution.
340 is greater than 3 standard deviations from the mean of the distribution.</span>
5 0
3 years ago
For what values of a and m does f(x) have a horizontal asymptote at y = 2 and a vertical asymptote at x = 1? f(x)=2x^m/x+a {a =
iVinArrow [24]

Answer:

See below

Step-by-step explanation:

f(x)=\frac{2x^{m} }{x+a}

f(x)=\frac{2x^{1} }{x-1}

If x=1, then 1-1=0, which implies a vertical asymptote at x=1 since dividing by 0 is undefined.

3 0
3 years ago
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