Difference of 2 perfec squares is
(a^2)-(b^2)
if the exponents are both even and the coeficient (the number in front) are perfect squares, then it is difference t 2 perfect squares
first one
8 is not perfect square
2nd one
(4e^4)^2-(9g^2)^2
third
25 is odd, so it cannot be split up into 2 nice numbers
4th
(11m^9)^2-(3n^5)^2
Answer:
x= 226/3 or 75.33333333333333333333333333333
Step-by-step explanation:
14y+82=6x-20
y=25
Sub y=25 into 14y+82=6x-20
14y+82=6x-20
14(25)+82=6x-20
Calculate as follows:
14(25)+82=6x-20
350+82=6x-20
432=6x-20
Add twenty to both sides:
432+20=6x-20+20
452=6x-0
452=6x
Divide both sides by 6
452=6x
452/6=6x/6
452/6=x
x= 226/3 or 75.33333333333333333333333333333
Answer:
Check below, please
Step-by-step explanation:
Step-by-step explanation:
1.For which values of x is f '(x) zero? (Enter your answers as a comma-separated list.)
When the derivative of a function is equal to zero, then it occurs when we have either a local minimum or a local maximum point. So for our x-coordinates we can say
2. For which values of x is f '(x) positive?
Whenever we have
then function is increasing. Since if we could start tracing tangent lines over that graph, those tangent lines would point up.
3. For which values of x is f '(x) negative?
On the other hand, every time the function is decreasing its derivative would be negative. The opposite case of the previous explanation. So
4.What do these values mean?
5.(b) For which values of x is f ''(x) zero?
In its inflection points, i.e. when the concavity of the curve changes. Since the function was not provided. There's no way to be precise, but roughly
at x=-4 and x=4
Answer:
P=0.147
Step-by-step explanation:
As we know 80% of the trucks have good brakes. That means that probability the 1 randomly selected truck has good brakes is P(good brakes)=0.8 . So the probability that 1 randomly selected truck has bad brakes Q(bad brakes)=1-0.8-0.2
We have to find the probability, that at least 9 trucks from 16 have good brakes, however fewer than 12 trucks from 16 have good brakes. That actually means the the number of trucks with good brakes has to be 9, 10 or 11 trucks from 16.
We have to find the probability of each event (9, 10 or 11 trucks from 16 will pass the inspection) . To find the required probability 3 mentioned probabilitie have to be summarized.
So P(9/16 )= C16 9 * P(good brakes)^9*Q(bad brakes)^7
P(9/16 )= 16!/9!/7!*0.8^9*0.2^7= 11*13*5*16*0.8^9*0.2^7=approx 0.02
P(10/16)=16!/10!/6!*0.8^10*0.2^6=11*13*7*0.8^10*0.2^6=approx 0.007
P(11/16)=16!/11!/5!*0.8^11*0.2^5=13*21*16*0.8^11*0.2^5=approx 0.12
P(9≤x<12)=P(9/16)+P(10/16)+P(11/16)=0.02+0.007+0.12=0.147
