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ankoles [38]
3 years ago
6

Write a decimal where the value of a digit is 1/10 as much as a digit in another place

Mathematics
1 answer:
zmey [24]3 years ago
6 0
The answer would be .66
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Determine whether each equation is a linear equation. ... –2x – 3 = y .... linear. 16. 4y. 2. + 9 = –4. SOLUTION: Since y is squared, the equationcannot be written in standard form.
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Tammy is at the dentist's office waiting on her appointment. She notices that the 6-inch-long minute hand is rotating around the
Elena L [17]
PART 1:55-21=35
             35/60=<span>.58333 
             360</span>×<span>.58333 =210 DEGREES
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PART 2: </span><span>(pi) x 2r x .58333 
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PART 4: </span><span>2.618 radians * 180/pi = 150° </span>
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7 0
3 years ago
Read 2 more answers
I needed help on this
Strike441 [17]

Answer:

Step-by-step explanation:

Let Freda's sum = x

Donnie has 3/4 x

He spends 63 dollars. His sum is now

3/4x - 63

Now the equation looks like this

6(3/4x - 63) = x            Remove the brackets

6*3/4 x - 378 =x

6 * 3/4 = 4 1/2

4 1/2 x - 378 = x           Add 378 to both sides

4 1/2 x = x + 378          Subtract x from both sides

3.5 x = 378                  Divide by 3.5

x = 378 /3.5

x = 108

Since x = 108, that's how much Freda had. (She spent nothing).

5 0
3 years ago
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mash [69]

Answer:

Harry stains his shirt

1/5= 20%

15%

7 0
3 years ago
Read 2 more answers
a collection of dimes and quarters is worth $19.85. There are 128 coins in all. How many of each type of coin are in the collect
PolarNik [594]

Number of dimes were 81 and number of quarters were 47

<em><u>Solution:</u></em>

Let "d" be the number of dimes

Let "q" be the number of quarters

We know that,

value of 1 dime = $ 0.10

value of 1 quarter = $ 0.25

<em><u>Given that There are 128 coins in all</u></em>

number of dimes + number of quarters = 128

d + q = 128 ------ eqn 1

<em><u>Also given that collection of dimes and quarters is worth $19.85</u></em>

number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 19.85

d \times 0.10 + q \times 0.25 = 19.85

0.1d + 0.25q = 19.85  -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 1,

d = 128 - q -------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

0.1(128 - q) + 0.25q = 19.85

12.8 - 0.1q + 0.25q = 19.85

12.8 + 0.15q = 19.85

0.15q = 7.05

<h3>q = 47</h3>

Therefore from eqn 3,

d = 128 - q

d = 128 - 47

<h3>d = 81</h3>

Thus number of dimes were 81 and number of quarters were 47

4 0
3 years ago
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