Answer:
QH = 227.8 km ≅ 228 km
Step-by-step explanation:
∵ The bearing from H to P is 084°
∵ The bearing from P to Q is 210°
∵ The distance from H to P = 340 km
∵ The distance from P to Q = 160 km
∴ The angle between 340 and 160 = 360 - 210 - (180 - 84) = 54°
( 180 - 84) ⇒ interior supplementary
By using cos Rule:
(QH)² = (PH)² + (PQ)² - 2(PH)(PQ)cos∠HPQ
(QH)² = 340² + 160² - 2(340)(160)cos(54) = 51904.965
∴ QH = 227.8 km ≅ 228 km
Answer:
333cm^2
Step-by-step explanation:
Divide the compound shape into the two separate parts, the rectangle and the triangle.
The rectangle measuring 18cm by 14cm, getting the area, use the formula length*width. This is 18*14= 252cm^2.
Then the triangle has the height, 9cm and base 18cm, finding the area use the formula, 1/2*base*height.
1/2*9*18= 81cm^2.
Add the two, 252+81= 333cm^2.
To find midpoint, we find the average or median of the two x terms and the average of the two y terms to find the right coordinate point. In this case, the average of -2 and 6 is 2, and the mean of 4 and -4 is 0, so the new coordinate point is (2,0).
18 is the absolute value of -18