We are given the equation <span>an = (n^2/ sqrt(n^3+4n)) and asked to determine if the function is divergent or convergent. In this case, we find the limit of the function as n approaches infinity.
an = </span><span> (n^2/ sqrt(n^3+4n))
lim (n to infinity ) = infinity / infinty: ;indeterminate
Using L'hopitals rule, we derive
</span><span>lim (n to infinity ) = 2 n / 0.5* ( </span><span>n^3+4n) ^-0.5 * (3 n2 +4) : infinity / infinity
again, we derive
</span>lim (n to infinity ) = 2 (0.25) (( n^3+4n) ^-0.5))*(3 n2 +4) / 0.5* ( 6n + 4) :infinity / infinity
<span>
again,
</span>lim (n to infinity ) = 2 (0.25) (6n + 4) / 0.5* ( 6)* 0.5 <span>(( n^3+4n) ^-0.5))</span>
this goes on and the function is divergent
Your answer should be 57.7 Hope this helped!!!
3600 if you multiply 40 to 80<span />
Here are the areas of the 3 separate shapes:
1. 27.5 m^2
2. 25.5 m^2
3. 27.5 m^2
As you can see, the 1st and 3rd shapes share the same total area, so those are the shapes you should select.
