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alexira [117]
3 years ago
15

Round 341,611 to the nearest thousand.

Mathematics
2 answers:
EastWind [94]3 years ago
8 0
342,000 I think so lol
Gemiola [76]3 years ago
4 0

Answer:

342000

Step-by-step explanation:

you just have to look at the thousands place and the hundreds place, if the hundreds place is five or more (up to nine) then you round up, if the hundreds place is 4 or less (down to 0) then you round down. In this case, the hundreds place is six which is greater then 5 so you round up the thousands place is 1 so you round up to 2 and the answer is 342000

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What is the Hcf of 24 and 42
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Answer:

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Step-by-step explanation:

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Malia works at a movie theater and is paid hourly. One month, she earned $388.80. The total amount she earns can be found using
Georgia [21]
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Is that the answer ur looking for ?
4 0
4 years ago
Read 2 more answers
A cylinder has a height of 6 meters and a diameter that is 6 times the measure of the height. Using 3.14 for pi, which of the fo
muminat

Answer:

The volume of the cylinder is 6,104.16 square meters.

Step-by-step explanation:

Given that a cylinder has a height of 6 meters and a diameter that is 6 times the measure of the height, to determine, using 3.14 for pi, which of the following can be used to calculate the volume of the cylinder, the following calculation must be done, knowing that the volume of a cylinder is determined by multiplying Pi by the height by the radius squared, and that the diameter of a circle is twice its radius:

3.14 x 6 x (6x3) ^ 2 = X

18.84 x 18 ^ 2 = X

18.84 x 324 = X

6,104.16 = X

Therefore, the volume of the cylinder is 6,104.16 square meters.

3 0
3 years ago
Read 2 more answers
The length of a rectangle is 4 m longer than its width. if the perimeter of the rectangle is 36 m , find its area.
ycow [4]
Answer:   The area of the rectangle is:  " 77 m² " .

__________________________________________________________
Note:  The formula for the area, "A" of a rectangle:

 →  A  =  L  *  w   ;

                 in which:  
     A = "area (of rectangle)" ; [in units of "m² " ; that is:  "square meters" ] ; 
                                     
     L = length = "(4 + w)" {in units of "meters (m)" } ;  
             
     w = width  {in units of "meters (m)" } ; 
_______________________________________________________

So;  " A = L * w " ;  

Substitute the known expression for the "length, L" ;  & rewrite the formula for the given area of OUR area for the rectangle in OUR GIVEN PROBLEM:

              →  A = (4 + w) * w '' ;
______________________________________________________

Note the formula for the perimeter, "P" ; 

 →  P = 2L + 2w  ; 

↔   2L + 2w = P 

 →  2L + 2w  = 36 m ;
_____________________________________________________
We want to find the "area" , "A" :
_____________________________________________________
Using the formula for the "perimeter, "P" (of the rectangle) ; & given that the perimeter is:  "36" (meters) ;  

 →  2L + 2w  = 36 ;

 →  Let us plug in the values for "Length (L)" & "width (w)" ; 

 →  2(w + 4)  + 2w = 36  ; 

So;   (2*w) + (2*4) + 2w = 36 ;  Solve for "w" ;

    →  2w + 8 + 2w = 36 ; 

    → Combine the "like terms" :

         + 2w + 2w = 4w ; 

   →  And rewrite: 

         4w + 8 = 36 ; 

Now, subtract "8" from EACH SIDE of the equation:

         4w + 8 − 8 = 36 <span>− 8 ; 
</span>
to get: 

         4w = 28 ; 

Now, divide EACH SIDE of the equation by "4" ; 
      to isolate "w" on EACH SIDE of the equation ; & to solve for "w" ; 

         4w / 4 = 28 / 4  ; 

           → w = 7 ;   → The "width" of the rectangle is:  " 7 m " .

Now, we can find the "length" of the rectangle:

The length, "L" , of the rectangle = 4 + w = 4 + 7 = 11 .
      
           →  L = 11 .  →  The "length" of the rectangle is:  " 11 m " .
___________________________________________________
 
Now, we can find the area, "A", of the rectangle.

 A = L * w  =  11 m * 7 m  =  " 77 m² " .

  →  The area of the rectangle is:  " 77 m² <span>" .
</span>__________________________________________________

To check our answer:
__________________________________________________
 
→  " P = 2L + 2w "  ; 

Given that "P = 36 m" ; 

Plug in "36 m" (for "P") ; into the equation ;

and plug in our calculated values for
                        "length, L" (which is "11 m") ; & "width, w" (which is "7 m") ; 

to see if the equation holds true ; that is, to see if both sides of the equation are equal ;
_______________________________________________________  

 →  36 m = ?  2L + 2w ?? ;

 →  36 m = ?  2(11 m) + 2(7 m) ?? ; 

 →  36 m = ?  22 m + 14 m ?? ; 

 →  36 m = ?  36 m ?  Yes! 
__________________________________________________
3 0
3 years ago
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