Work done by force is given by formula

now here work done against friction is given so force of friction here is

It moved by three corridors with each measures

so total distance will be

now from above formula of work done we will say


so above is the work done to move three corridors
Answer:
A = -14.87 i ^ + 8.42 j ^ + 0 k ^
B = -25.41 i ^ -12.0 j ^ + 0 k ^
Explanation:
For this exercise let's use trigonometry by decomposing to vectors
vector A
module 17.1 with an angle of 150.5 counterclockwise.
Sin 150.5 =
/ A
cos 150.5 = Ax / A
A_{y} = A sin 150.5 = 17.1 sin 150.5
Aₓ = A cos 1505 = 172 cos 150.5
A_{y} = 8,420
Aₓ = -14.870
the vector is
A = -14.87 i ^ + 8.42 j ^ + 0 k ^
Vector B
= 28.1 sin 205.3
Bₓ = 28.1 cos 205.3
B_{y} = -12.009
Bₓ = -25.405
the vector is
B = -25.41 i ^ -12.0 j ^ + 0 k ^
The possible units for impulse would be:
<span>(N. s)
</span><span>(kg. m/s)</span>
Answer:
Explanation:
Given
initial velocity 
At maximum height velocity of ball is zero
using

where v=final velocity
u=initial velocity
a=acceleration
s=displacement



time taken by the ball to reach the maximum height




At
height of ball is




i.e. ball is moving downward
height at 


I would assume you answer them by doing the math required.