All categories

3 years ago

What type of sound do the thinner

Physics

2 answers:

Svetach [21]3 years ago

3 0

A im pretty sure lol i think yes

Goryan [66]3 years ago

3 0

Answer:

Explanation:

I'm not perfectly sure so check again

You might be interested in

You are a nurse in a hospital. You are told to move a patient through three corridors each measuring 14.33 meters. Because of fr

dimulka [17.4K]

Work done by force is given by formula

$W = F.d$

now here work done against friction is given so force of friction here is

$F_f = 848 N$

It moved by three corridors with each measures

$d = 14.33 m$

so total distance will be

$s = 14.33 \times 3 = 43 m$

now from above formula of work done we will say

$W = 848 \times 43$

$W = 36464 J$

so above is the work done to move three corridors

3 0

3 years ago

Vectors A and B lie in the xy ‑plane. Vector A has a magnitude of 17.1 and is at an angle of 150.5∘ counterclockwise from the +x

IRINA_888 [86]

Answer:

A = -14.87 i ^ + 8.42 j ^ + 0 k ^

B = -25.41 i ^ -12.0 j ^ + 0 k ^

Explanation:

For this exercise let's use trigonometry by decomposing to vectors

vector A

module 17.1 with an angle of 150.5 counterclockwise.

Sin 150.5 = $A_{y}$ / A

cos 150.5 = Ax / A

A_{y} = A sin 150.5 = 17.1 sin 150.5

Aₓ = A cos 1505 = 172 cos 150.5

A_{y} = 8,420

Aₓ = -14.870

the vector is

A = -14.87 i ^ + 8.42 j ^ + 0 k ^

Vector B

$B_{y}$ = 28.1 sin 205.3

Bₓ = 28.1 cos 205.3

B_{y} = -12.009

Bₓ = -25.405

the vector is

B = -25.41 i ^ -12.0 j ^ + 0 k ^

5 0

3 years ago

Please send help my way. 10 points to the brainliest

antoniya [11.8K]

The possible units for impulse would be:
<span>(N. s)
</span><span>(kg. m/s)</span>

4 0

4 years ago

You throw a ball straight up. The ball has an initial speed of 11.2 m/s when it leaves your hand What is the maximum height the

Jet001 [13]

Answer:

Explanation:

Given

initial velocity $u=11.2\ m/s$

At maximum height velocity of ball is zero

using

$v^2-u^2=2as$

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

$(0)^2 -(11.2)^2=2\times (-9.8)\times (s)$

$s=\frac{11.2^2}{2\times 9.8}$

$s=6.4$

time taken by the ball to reach the maximum height

$v=u+at$

$0=11.2-9.8\times t$

$t=\frac{11.2}{9.8}$

$t=1.142\ s$

At $t=2\ s$ height of ball is

$h=ut+\\frac{1}{2}at^2$

$h=11.2\times 2-\frac{1}{2}9.8\times (2)^2$

$h=22.4-19.6$

$h=2.8\ m$

i.e. ball is moving downward

height at $v=5\ m/s$

$v^2-u^2=2as$

$s=\frac{25-125.4}{2\times (-9.8)}$

$s=5.12\ m$

8 0

3 years ago

How do you answer number 3 a and b?

netineya [11]

I would assume you answer them by doing the math required.

7 0

4 years ago