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3 years ago

The space around a charge or a pole in which a force is experienced is called a _______.

2 answers:

7 0

The space around a charge or a pole in which a force is experienced is called a magnetic field. And a cluster of aligned magnetic atoms is a magnetic domain. When the clustered regions are aligned with one another, they form a magnet.

Hoochie [10]3 years ago

4 0

Answer:

field

Explanation:

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The city council is considering discussing whether or not to put fluoride in the city's water supply. Many other towns add it al

umka2103 [35]

They should look for a report from an independent scientific research firm,
even if they have to pay for it.

In preparing its report, the firm would have already surveyed many of the 
citizens from several other towns that currently add fluoride to their water,
plus a lot of other relevant medical research on the subject.

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3 years ago

Read 2 more answers

A caterpillar crawls 20 feet in 5 minutes. What is the caterpillars crawling speed?

Pavel [41]

The equation is
s= d/t

In this case you would have to write it out as:
s= 20/5
Speed = 4

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3 years ago

Does the world actually end on April 21, 2021?

Setler [38]

Answer:

No? Umm Hi Btw I Know You Might Now Give Me Brainliest But Can I Please Have Brainliest I Had Brainliest On My other accoun.t But The Next Day It Got hacke.d That's Why Im Asking I Kept Trying To Login To My Hack.ed Account Then A Thing That says Your account Got Haccked Shows Up Everytime But Now ITs NoT Saying My Account got hacke.d anymore It Just Wont Let Me in Now.

Explanation:

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3 years ago

A thin uniform rod of mass M and length L is bent at its center so that the two segments are now perpendicular to each other. Fi

Tatiana [17]

Answer:

(a) I_A=1/12ML²

(b) I_B=1/3ML²

Explanation:

We know that the moment of inertia of a rod of mass M and lenght L about its center is 1/12ML².

(a) If the rod is bent exactly at its center, the distance from every point of the rod to the axis doesn't change. Since the moment of inertia depends on the distance of every mass to this axis, the moment of inertia remains the same. In other words, I_A=1/12ML².

(b) The two ends and the point where the two segments meet form an isorrectangle triangle. So the distance between the ends d can be calculated using the Pythagorean Theorem:

$d=\sqrt{(\frac{1}{2}L) ^{2}+(\frac{1}{2}L) ^{2} } =\sqrt{\frac{1}{2}L^{2} } =\frac{1}{\sqrt{2} } L=\frac{\sqrt{2} }{2} L$

Next, the point where the two segments meet, the midpoint of the line connecting the two ends of the rod, and an end of the rod form another rectangle triangle, so we can calculate the distance between the two axis x using Pythagorean Theorem again:

$x=\sqrt{(\frac{1}{2}L)^{2}-(\frac{\sqrt{2}}{4}L) ^{2} } =\sqrt{\frac{1}{8} L^{2} } =\frac{1}{2\sqrt{2}} L=\frac{\sqrt{2}}{4} L$

Finally, using the Parallel Axis Theorem, we calculate I_B:

$I_B=I_A+Mx^{2} \\\\I_B=\frac{1}{12} ML^{2} +\frac{1}{4} ML^{2} =\frac{1}{3} ML^{2}$

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3 years ago

A 68 kg crate is dragged across a floor by pulling on a rope attached to the crate and inclined 13° above the horizontal. (a) if

Blababa [14]

Answer: Therefore, x component: Tcos(24Â°) - f = 0 y component: N + Tsin(24Â°) - mg = 0 The two equations I get from this are: f = Tcos(24Â°) N = mg - Tsin(24Â°) In order for the crate to move, the friction force has to be greater than the normal force multiplied by the static coefficient, so... Tcos(24Â°) = 0.47 * (mg - Tsin(24Â°)) From all that I can get the equation I need for the tension, which, after some algebraic manipulation, yields: T = (mg * static coefficient) / (cos(24Â°) + sin(24Â°) * static coefficient) Then plugging in the values... T = 283.52. Reference https://www.physicsforums.com/threads/difficulty-with-force-problems-involving-friction.111768/

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3 years ago