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FinnZ [79.3K]
2 years ago
10

Students are asked to conduct an investigation on the mixing of color. They have three flashlights, each covered with a piece of

colored acetate (a transparent plastic). One flashlight is red, one is green, and one is blue. They shine the lights against a white background and observe that when the colors are mixed together, they see a white light. The students then hold a hand in front of the white background and switch on the lights one at a time. They record their observations for the color of the object and its shadow. They repeat this experiment with all three lights on and record the shadows they observe. Which best explains the difference in the results obtained for the shadow colors with all three lights on?
Physics
1 answer:
kkurt [141]2 years ago
3 0

Block the red and green lights and you get a blue shadow. Block all three lights, you get a black shadow.Block one of the three lights, you get a shadow whose colour is a mixture of the two other colours.

<h3>What is colour spectrum?</h3>

The distribution of colors produced when light is dispersed by a prism.

In this demonstration,

Students experiment with red, green, and blue light to get different shadow colours.

Primary colors are not a fundamental property of light but are related to the physiological response of the eye to light. Light is a continuous spectrum of all of the wavelengths that can be detected by the human eye.

The human eye normally contains only three types of colour ranges of the colour spectrum.

Humans and other species with three such types of color receptors are known as trichromats.

The R, G, B cones are most sensitive to the red, green, and blue wavelengths.

The colours each receptor is the most sensitive to. The blue cone will also pick up purple, blue, and green hues.

Green cones will pick up purple, blue, green, yellow, and orange hues. Red cones will pick up purple, blue, green, yellow, orange, and red hues. The sensitivities of the three cones overlap to let us perceive all visible colours.

Hence,

When red light, blue light, and green light stimulate the three colour receptors on our retinas equally, the signal gets blended in our brain and we see "white" light.

This is why we see sunlight as white light, not as its individual colours.

Slight changes in the relative signals of the cones enable us to see a myriad of different colour combinations, which is why we "see" more than just three colours.

In this demonstration, coloured filters are affixed to flashlights.

The coloured filters block some wavelengths and let others through. The red-filtered flashlight puts out wavelengths from red through to orange and yellow. The green-filtered flashlight puts out yellow, green and blue wavelengths. The blue-filtered flashlight puts out green, blue, and purple wavelengths.

When the three coloured light bulbs all shine on the same surface, we see all the wavelengths from red through to purple, which we perceive as white.

With these three coloured lights you can make shadows of seven different colours:

Blue, red, green, black, cyan (blue-green), magenta (pink), and yellow.

If you block two of the three lights, you get a shadow of the third color.

  • Block the red and green lights and you get a blue shadow.
  • Block all three lights, you get a black shadow.
  • Block one of the three lights, you get a shadow whose colour is a mixture of the two other colours.

Learn more about colour spectrum here:

brainly.com/question/1320671

#SPJ1

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Answer:

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Explanation:

Let's work this problem by finding the distance between the balloon and the motorcycle and then drift for the speed change of the distance

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Motorcycle

      x = v₀ₓ t

Distance, let's use Pythagoras' theorem

      R² = x² + y²

      R² = (v₀ₓ t)² + (y₀ + v_{oy} t)²

     v₀ₓ = 88 ft / s

     v_{oy} = 8 ft / s

     y₀ = 150 ft

     R² = (8 t)² + (150 + 8 t )²

     R² = 64 t² + (150 + 8t )²

This is the expression for the distance between the two bodies, the rate of change is the derivative with respect to time (d / dt)

         2RdR / dt = 64 2 t + 2 (150 + 8t) 8

        dR / dt = [64 t + (1200 + 64t )] / R

dR/dt = (1200 +128 t)/R

Let's calculate for the time of 10 s

        dR / dt = (1200 + 128 10) / R = 2480 /R

       R = √ [64 10² + (150 + 8 10)²

       R = √ [6400 + 52900]

       R = 243.5 ft

       dR / dt = (2480) / 243.5

       dR / dt = 10.2 ft / s

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Answer:

   W₃ = 3310.49 J ,  W3 = 3310.49 J

Explanation:

We can solve this exercise in parts, the first with acceleration, the second with constant speed and the third with deceleration. Therefore it is work we calculate it in these three sections

We start with the part with acceleration, the distance traveled is y = 5.90 m and the final speed is v = 2.30 m / s. Let's calculate the acceleration with kinematics

       v2 = v₀² + 2 a₁ y

as they rest part of the rest the ricial speed is zero

        v² = 2 a₁ y

        a₁ = v² / 2y

        a₁ = 2.3² / (2 5.90)

        a₁ = 0.448 m / s²

with this acceleration we can calculate the applied force, using Newton's second law

         F -W = m a₁

         F = m a₁ + m g

         F = m (a₁ + g)

         F = 69 (0.448 + 9.8)

         F = 707.1 N

Work is defined by

         W₁ = F.y = F and cos tea

As the force lifts the man, this and the displacement are parallel, therefore the angle is zero

          W₁ = 707.1 5.9

           W₁ = 4171.89 J  W3 = 3310.49 J

Let's calculate for the second part

the speed is constant, therefore they relate it to zero

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           F = m g

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the job is

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finally the third part

in this case the initial speed is 2.3 m / s and the final speed is zero

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            0 = vo2₀² + 2 a₂ y

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we calculate the force

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            F = 60 (9.8 - 0.448)

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we calculate the work

            W3 = F and

            W3 = 561.1 5.9

          W3 = 3310.49 J

total work

          W_total = W1 + W2 + W3

          W_total = 4171.89 +3469.2 + 3310.49

           w_total = 10951.58 J

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