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FinnZ [79.3K]
2 years ago
10

Students are asked to conduct an investigation on the mixing of color. They have three flashlights, each covered with a piece of

colored acetate (a transparent plastic). One flashlight is red, one is green, and one is blue. They shine the lights against a white background and observe that when the colors are mixed together, they see a white light. The students then hold a hand in front of the white background and switch on the lights one at a time. They record their observations for the color of the object and its shadow. They repeat this experiment with all three lights on and record the shadows they observe. Which best explains the difference in the results obtained for the shadow colors with all three lights on?
Physics
1 answer:
kkurt [141]2 years ago
3 0

Block the red and green lights and you get a blue shadow. Block all three lights, you get a black shadow.Block one of the three lights, you get a shadow whose colour is a mixture of the two other colours.

<h3>What is colour spectrum?</h3>

The distribution of colors produced when light is dispersed by a prism.

In this demonstration,

Students experiment with red, green, and blue light to get different shadow colours.

Primary colors are not a fundamental property of light but are related to the physiological response of the eye to light. Light is a continuous spectrum of all of the wavelengths that can be detected by the human eye.

The human eye normally contains only three types of colour ranges of the colour spectrum.

Humans and other species with three such types of color receptors are known as trichromats.

The R, G, B cones are most sensitive to the red, green, and blue wavelengths.

The colours each receptor is the most sensitive to. The blue cone will also pick up purple, blue, and green hues.

Green cones will pick up purple, blue, green, yellow, and orange hues. Red cones will pick up purple, blue, green, yellow, orange, and red hues. The sensitivities of the three cones overlap to let us perceive all visible colours.

Hence,

When red light, blue light, and green light stimulate the three colour receptors on our retinas equally, the signal gets blended in our brain and we see "white" light.

This is why we see sunlight as white light, not as its individual colours.

Slight changes in the relative signals of the cones enable us to see a myriad of different colour combinations, which is why we "see" more than just three colours.

In this demonstration, coloured filters are affixed to flashlights.

The coloured filters block some wavelengths and let others through. The red-filtered flashlight puts out wavelengths from red through to orange and yellow. The green-filtered flashlight puts out yellow, green and blue wavelengths. The blue-filtered flashlight puts out green, blue, and purple wavelengths.

When the three coloured light bulbs all shine on the same surface, we see all the wavelengths from red through to purple, which we perceive as white.

With these three coloured lights you can make shadows of seven different colours:

Blue, red, green, black, cyan (blue-green), magenta (pink), and yellow.

If you block two of the three lights, you get a shadow of the third color.

  • Block the red and green lights and you get a blue shadow.
  • Block all three lights, you get a black shadow.
  • Block one of the three lights, you get a shadow whose colour is a mixture of the two other colours.

Learn more about colour spectrum here:

brainly.com/question/1320671

#SPJ1

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Racing greyhounds are capable of rounding corners at very high speeds. A typical greyhound track has turns that are 45 m diamete
Readme [11.4K]

Answer:

In m/s^2:

a=11.3778 m/s^2

In units of g:

a=1.161 g

Explanation:

Since the racing greyhounds are capable of rounding corners at very high speed so we are going use the following formula of acceleration for circular paths.

a=\frac{v^2}{r}

where:

v is the speed

r is the radius

Now,

a=\frac{16^2}{45/2}\\ a=11.3778 m/s^2

In g units:

a=\frac{11.3778\ g}{9.8}\\ a=1.161\ g

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3 years ago
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A tuning fork vibrating at 508 Hz falls from rest and accelerates at 9.80 m/s^2. How far below the point of release is the tunin
JulijaS [17]

Answer:

Explanation:

given,

tuning fork vibration = 508 Hz

accelerates = 9.80 m/s²

speed of sound = 343 m/s

observed frequency = 490 Hz

f_s = f(\dfrac{v}{v-(-v_s)})

f_s = f(\dfrac{v}{v+v_s})

v_s = v[\dfrac{f_s}{f_o}-1]

      = 343[\dfrac{508}{490}-1]

      v_s=12.6 m/s

distance the tunning fork has fallen

y_1=\dfrac{v^2}{2a_y}

     =\dfrac{12.6^2}{2\times 9.8}

     =8.1 m

now, time required for the observed will be

t = \dfrac{8.1}{343} = 0.023 s

now, for the distance calculation

y_2 = u\ t + \dfrac{1}{2}at^2

  = 12.6\times 0.023 +\dfrac{1}{2}\times 9.8 \times 0.023^2

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total distance

 = 8.1 + 0.293 = 8.392 m

3 0
3 years ago
1. The sun radiates light from space to heat a swimming pool on Earth.
scoundrel [369]

Answer:

c. Light energy to thermal energy

Explanation:

The energy from the sun comes in the form of light energy but is converted to thermal energy.

7 0
1 year ago
two negative charges that are both -3.0 C push each other apart with a force of 19.2 N how far apart are the charges
Hoochie [10]
The electrostatic force between two charges q1 and q2 is given by
F=k_e  \frac{q_1 q_2}{r^2}
where k_e =8.99 \cdot 10^9 N m^2 C^{-2} is the Coulomb's constant and r is the distance between the two charges.

If we use F=19.2 N and q1=q2=-3.0 C, we can find the value of r, the  distance between the two charges by re-arranging the previous formula:
r= \sqrt{k_e \frac{q_1 q_2}{F} }= \sqrt{ 8.99 \cdot 10^9 N m^2 C^{-2} \frac{(-3.0C)^2}{19.2 N} } =6.49 \cdot 10^4 m=64.9 km
5 0
3 years ago
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