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4 years ago

How do you answer number 3 a and b?

Physics

1 answer:

netineya [11]4 years ago

7 0

I would assume you answer them by doing the math required.

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Explain what happens to the energy in a group in a system if one object loses energy according to the Law of Conservation of Ene

konstantin123 [22]

energy never disappears, for example, if you give some kinetic energy to a ball and it stops few seconds later, friction steals this energy to ground which ball was going on. "Law of Conservation of Energy" tell us that energy can't disappear

5 0

3 years ago

Position can best be described as

Elan Coil [88]

B. The location of an object.

The term position describes the location of a place with respect to some reference point called origin.

5 0

4 years ago

An airplane is flying through the air at a speed of 150 mph at a heading of 60 degrees. if the wind is blowing at 20 mph from th

Crazy boy [7]

Answer:

Explanation:

Given

speed of plane 150 mph

heading $60^{\circ}$

wind is blowing at 20 mph from south-east

velocity of plane w.r.t. wind

$v_{pw}=150(\cos 60\hat{i}+\sin 60\hat{j})$

$v_{w}=20(\cos 45\hat{i}-\sin 45\hat{j})$

$v_{p}=v_{pw}+v_{w}$

$v_{p}=(150\cos 60+20\cos 45)\hat{i}+(150\sin 60-20\sin 45 )\hat{j}$

$v_{p}=89.14\hat{i}+115.76\hat{j}$

$|v_{p}|=146.103 m/s$

(b)after 30 minutes

Plane traveled in x direction $=89.14\times 0.5=44.57 miles$

Plane in Y direction $=115.76\times 0.5=57.88 miles$

Total distance $=\sqrt{x^2+y^2}=73.05 miles$

direction $tan\theta =\frac{115.76}{89.14}=1.298$

$\theta =52.38^{\circ}$ w.r.t east

4 0

3 years ago

At a local swimming pool, the diving board is elevated h = 9.5 m above the pool's surface and overhangs the pool edge by L = 2 m

eimsori [14]

Answer:

1) The time it takes the diver to move off the end of the diving board to the pool surface, $t_w$ , is approximately 1.392 seconds

2) The horizontal distance from the edge of the pool to where the diver enters the water, $d_w$ , is approximately 5.76 meters

Explanation:

1) The given parameters are;

The height of the diving board above the pool's surface, h = 9.5 m

The length by which the diving board over hangs the pool L = 2 m

The speed with which the diver runs horizontally along the diving board, v₀ = 2.7 m/s

Taking $t_w$ = The time it takes the diver to move off the end of the diving board to the pool surface

Therefore, we have from the equation of free fall;

h = 1/2 × g × $t_w$ ²

Where;

g = The acceleration due to gravity = 9.81 m/s²

Substituting the values, gives;

9.5 = 1/2 × 9.81 × $t_w$ ²

$t_w$ = √(9.5/(1/2 × 9.81)) ≈ 1.392 s

The time it takes the diver to move off the end of the diving board to the pool surface = $t_w$ ≈ 1.392 s

2) The horizontal distance, $d_w$ , in meters from the edge of the pool to where the diver enters the water is given as follows;

$d_w$ = L + v₀ × $t_w$ = 2 + 2.7× 1.392 ≈ 5.76 m

∴ The horizontal distance from the edge of the pool to where the diver enters the water ≈ 5.76 meters.

7 0

3 years ago

Name an example of a population you might find in a forest.

ki77a [65]

Answer:

deers...?

Explanation:

7 0

3 years ago

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