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3 years ago

Find the distance between (1, 4) and (-2, 0)

Mathematics

1 answer:

Vanyuwa [196]3 years ago

4 0

Answer:

$\boxed {d = 5}$

Step-by-step explanation:

Use the Distance Formula to help you determine the distance between two given points:

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}$

First point: $(x_{1}, y_{1})$

Second Point: $(x_{2}, y_{2})$

-Apply the two given points onto the formula:

First point: $(1, 4)$

Second point: $(-2, 0)$

$d = \sqrt{(-2 - 1)^{2} + (0 - 4)^{2}}$

-Solve for the distance:

$d = \sqrt{(-2 - 1)^{2} + (0 - 4)^{2}}$

$d = \sqrt{(-3)^{2} + (-4)^{2}}$

$d = \sqrt{9 + 16}$

$d = \sqrt{25}$

$\boxed {d = 5}$

Therefore, the distance is $5$ .

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PLEASE HELP!! NO LINKS!! GIVING 20 POINTS AWAY!!

Kruka [31]

Answer:

m∠N = 32°

NQ = 106°

When finding inscribed angles like ∠N with the intercepted arc, the equation is ∠N=1/2MP. (Inscribed angles are always half the degree of the arc length.) Plug in the corresponding value to get ∠N=1/2(64) to get 32°. When finding the angle of the intercepted arc with inscribed angles like NQ, the equation is NQ=2(∠P). Plug in the corresponding value to get 2(53) to get 106°.

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3 years ago

Read 2 more answers

A litter of puppies consists of black puppies and white puppies. A

BartSMP [9]

We want to see if the first selection is dependent on the second selection, we will see that no, the first selection can not depend on a selection that did not happen yet.

So the situation is:

We have a group of puppies, some are black, some are white.

Let's say that there are N puppies in total, n₁ are black, n₂ are white, such that:

n₁ + n₂ = N

Now we have that the first selection, event A, is a black puppy. The probability is just the quotient between the number of black puppies and the total number of puppies:

q = n₁/N

Then now we have:

N - 1 puppies in total.
n₁ - 1 black puppies
n₂ white puppies.

Now for the second selection, event B, the probability of selecting a white puppy is:

P = n₂/(N - 1)

Notice that because there are fewer black puppies than before (because we took one) the denominator decreases, thus, the probability of getting a white puppy increases.

So clearly event B depends on event A.

Now the question is:

Is A dependent on B?

No, A can not depend on event B, because event A happens first. The probability of the first event is always q = n₁/N.

If you want to learn more, you can read:

brainly.com/question/12138717

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3 years ago

Answer this in pictures and number of words

qaws [65]

Answer: Tom's solution is incorrect.

Step-by-step explanation:

When you add 3/6 + 1/2 it equals ?.

3 + 1 = ?

6 + 2 = ?

We must have common denominators to do this problem.

So we must have 6 as our common denominator.

So 2 x 3 = 6. But we have to do the same to the Numerator.

So 1 x 3 = 3.

Now our problem is 3/6 + 3/6 = ?

3 + 3 = 6/6. Or 1

1 does not equal 4/12 or 1/3. So it makes it Incorrect.

What you should say:

Tom is incorrect, it is because 3/6 + 1/2 = 1, 1 does not equal 4/12 or 1/3. So, it makes it reasonable for the correct answer to be Incorrect

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3 years ago

Read 2 more answers

6) (after 2.3) Consider the infinite system of linear equations in two variables given by ax + by = 0 where (a, b) moves along t

Paraphin [41]

Answer:

Step-by-step explanation:

Given infinite system of linear equations is ax + by = 0

when (a,b) moves along unit circle in plane.

a) system having unique system (0, 0)

Since two of equation in thus system will be

$1.x+0.y=0\\x=0$

and

$0.x+1.y=0\\y=0$

It is clear that x = 0, y= 0 is the only solution

b) Linear independent solution in this system gives some set of solutions

$1.x+0.y=0\\\x=0$

and

$0.x+1.y=0\\y=0$

Vector form is

$\left[\begin{array}{ccc}1&0\\0&1\end{array}\right] =I$

c) for this equation if add 0x +0y = 0 to system , Nothing will change

Because [0,0] satisfies that equation

d) If one of the equation is ax + by = 0.00001

where 0.00001 is small positive number

so, the system will be inconsistent

Therefore, the system will have no solution.

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3 years ago

Which angles are vertical to each other? E B F G C A D

lorasvet [3.4K]

I’m thinking it’s A ???

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4 years ago