The genetic make-up of the offspring is the A.phenotype B.genotype
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Answer:
Let the "barred" allele be caller B and the "non-white" allele b. Since chickens use chromosomes and
to determine sex, hens would have chromosomes
, and roosters would have chromosomes
. A Z-linked gene is represented as a superscript on the
chromosome,
for the dominant allele and
for the ressesive allele.
A barred hen would have a copy of B on its Z chromosome, a non-barred rooster would have both copies of b on both Z chromosomes. Using Punnet squares to represent the crosses we get the following cases:
That is a ratio of two barred heterozygote roosters to two non-barred hens. Crossing them we get:
That is a ratio of one barred heterozygote rooster to one barred hen to one non-barred rooster to one non barred hen.