Answer: 4. 292+13n
Step-by-step explanation:
Jerome noticed the following house numbers on his street
305,318,331,344. This is an arithmetic sequence. The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = 305
d = 318 - 305 = 13
The expression that can be used to determine the Nth House number on his street is
Tn = 305 + (n - 1)13
Tn = 305 + 13n - 13
Tn = 13n + 305 - 13
Tn = 13n + 292
$4,950 because 6.5 of 3000 is 195 so multiply that by 10
11m-6m = 22+8
5m = 30
m = 6
Hope I helped :)
If u were to draw this out, u would have the shape of a right triangle....with the legs being 3 miles and 4 miles......and a straight line would be the hypotenuse. So we use the pythagorean theorem.
a^2 + b^2 = c^2
3^2 + 4^2 = c^2
9 + 16 = c^2
25 = c^2
sqrt 25 = c
5 = c
so Jimmy is 5 miles from home
(a) No doubt your textbook tells you that for a uniform distribution on the interval [a, b]:
.. mean = (a+b)/2 = (2.5 +30)/2 = 16.25
.. variance = (b -a)^2/12 = 27.5^2/12 = 63 1/48
(b) Likewise, from your text
.. p(x) = (x-a)/(b-a) = (x -2.5)/27.5
.. cdf(x) = p(x)^2 = (x -2.5)^2/756.25 . . . cumulative distribution function
(c) cdf(15) ≈ 0.2066 . . . . . . . . . . . probability of being 15 or less
.. cdf(20) -cdf(15) ≈ 0.1983 . . . . . probability of being between 15 and 20
(d) cdf(μ+σ) -cdf(μ-σ) ≈ 0.5774 . . . probability of being withing 1σ of the mean
.. cdf(μ+2σ) -cdf(μ-2σ) = 1 . . . . . . . the entire distribution is within 2σ of the mean