The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:

Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
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Answer:
what graph show me the graph
Step-by-step explanation:
Answer:850
Step-by-step explanation:
To find this 2% of x= 17
2/100×x=17
2x/100=17
2x=1700
x=850
A change to the inside of the function notation is always a left/right or horizontal change to the graph.
Answer: A
Subtracting 5 actually shifts the graph to the right by 5 units. It's counter-intuitive and there are many ways to explain why it's the opposite of what you think it'd do, but it is a shift to the right by 5 units.
PS
A change outside the f(x) notation is an up/down or vertical change to the graph.
I think it might be pairs 2 & 3