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4 years ago

michael is 3 times as old as brandon. 18 years ago, Michael was 9 times as old as brandon. how old is michael now

Mathematics

1 answer:

Ber [7]4 years ago

8 0

Let Brandon be b. Then Michael is 3b. So:

3b-18=9(b-18)

3b-18=9b-162

6b=144

b=24

3b=72

Brandon is 24, Michael is 72.

Hope this helped!

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Step-by-step explanation:

In order to find the inverse of the equation, we do a variable change, since we are finding the inverse, :

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Second divide by 9

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$y'^{2}$ = (x + 4)/9

Now you will have to clear y, with the square root.

$[tex]y'^{\frac{2}{2}} = \sqrt{x + 4} / \sqrt{9}$ [/tex] =

Simplifying terms

$y' = \frac{\sqrt{x+4}}{3}$

$f^{-1}(x) = \frac{\sqrt{x+4}}{3}$

You can check the answer by doing the evaluation of the following equation:

(f o $f^{-1}$ ) (x)

substitute the equation for y' or inverse function $f^{-1}$

f( $\frac{\sqrt{x+4} }{3}$ )

Now substitue the value into f(x)

You will have

$= 9(\frac{\sqrt{x+4} }{3}} )^{2} - 4\\\\Solving\\\\9(\frac{{x+4} }{9}} ) - 4$

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