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kupik [55]
2 years ago
13

What is the equilibrium constant expression for the reaction below? H2 (g) + I2 (g) → 2 HI(g)

Chemistry
1 answer:
brilliants [131]2 years ago
8 0
<h3>Further explanation</h3>

Given

Reaction

H₂ (g) + I₂ (g) → 2HI(g)

Required

The equilibrium constant

Solution

The equilibrium constant is the value of the product in the equilibrium state of the substance in the right (product) divided by the substance in the left (reactant) with the exponents of each reaction coefficient

The equilibrium constant for reaction  

pA + qB ⇒ mC + nD  

\large {\boxed {\bold {K ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}

So for the above reaction :

\tt K=\dfrac{[HI]^2}{[H_2][I_2]}

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When calcium forms an ion that has the same number of outer electrons as which noble gas?
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The answer is 4 krypton
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3 years ago
Which statement most completely defines a wave? *
Svetllana [295]

Answer:

A wave transfers energy through a medium or empty space without transporting matter.

Explanation:

  • A wave is a transmission of a disturbance from one point known as the source to another.
  • Waves may transfer energy through a material medium or a vacuum without transporting matter.
  • Waves that transfer energy from one point to another through a material medium are known as mechanical waves.
  • Electromagnetic waves, on the other hand, are those that do not require a material medium for transmission, the transfer of energy is through a vacuum.
  • Waves can also be either transverse or longitudinal waves based on the vibration of particles relative to the direction of wave motion.
4 0
2 years ago
When an aluminum cube of edge 0.100 m and temperature T0= 5.00°C is submerged in a bucket of water, the level of the water rises
vodka [1.7K]

Answer:

5.52cm³ of water will rise and might spill over the edge

Explanation:

Use the change in volume of a liquid with changing temperature equation which is written as

ΔV = β x V₀ x ΔT, where β is the coefficient of expansion, V₀ is the volume being submerged and ΔT is the difference in temperature

ΔV = (69 x 10⁻⁶) x (0.1 x 0.1 x 0.1) x (85 - 5)

ΔV = 5.52 x 10⁻⁶ m³

ΔV = 5.52cm³

7 0
3 years ago
Flourine is more reactive than chlorine​
IRISSAK [1]
Justification for your answer

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

Chlorine is less reactive than fluorine because the outer electrons in a chlorine atom are further from the nucleus than the outer electrons in a fluorine atom. It is harder for a chlorine atom to gain an electron than it is for a fluorine atom.

There are three things to consider every single time relative reactivity is unknown; atomic radius, shielding, and number of electrons. The reactivity is the halogens ability to gain an electron, so number of electrons already in the atom plays a vital role. Chlorine has more electrons so repels a reacting electron with greater force than fluorine, making it less likely to react.

Fluorine also has fewer electron shells than chlorine, so there are fewer electrons between the positive nucleus and the reacting electron to essentiallly block, or weaken, the electromagnetic attraction. This is shielding. Lastly, fluorine is much smaller molecule than chlorine, and the shorter distance, or radius, between the nucleus and the electron again makes it more likely to attract the electron and react to gain a noble gas configuration.

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖
7 0
3 years ago
Read 2 more answers
A chemistry student must write down in her lab notebook the concentration of a solution of sodium hydroxide. The concentration o
taurus [48]

Answer:

The concentration the student should write down in her lab is 2.2 mol/L

Explanation:

Atomic mass of the elements are:

Na: 22.989 u

S: 32.065 u

O: 15.999 u

Molar mass of sodium thiosulfate, Na2S2O3 = (2*22.989 + 2*32.065 + 3*15.999) g/mol = 158.105 g/mol.

Mass of Na2S2O3 taken = (19.440 - 2.2) g = 17.240 g.

For mole(s) of Na2S2O3 = (mass taken)/(molar mass)

= (17.240 g)/(158.105 g/mol) = 0.1090 mole.

Volume of the solution = 50.29 mL = (50.29 mL)*(1 L)/(1000 mL)

= 0.05029 L.

To find the molar concentration of the sodium thiosulfate solution prepared we use the formula:

= (moles of sodium thiosulfate)/(volume of solution in L)

= (0.1090 mole)/(0.05029 L)

= 2.1674 mol/L

6 0
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