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3 years ago

Which statement best describes the effects chemicals may have on the

Chemistry

2 answers:

frutty [35]3 years ago

7 0

The answer is B. So yeah

FromTheMoon [43]3 years ago

4 0

Some chemicals may help the environment

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Why are dark matter and dark energy described as "dark"? A. Because they emit blackbody radiation. B. Because they absorb light.

VMariaS [17]

Answer:

D. Because we cannot easily detect them.

Explanation:

Dark matter are called dark because using existing astronomical instruments we are blinded to them. Dark matter and dark energy are difficult to detect and properly observe. As we know that the whole universe is made up of matter, some of the matter do not interact with the electromagnetic radiations which makes undetectable.

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4 years ago

How many atoms are in 25.0 grams of carbon?

mars1129 [50]

mol = 25/12

= 2.083 mol

1 mol = 6.02 × 10^23 atoms

2.083 mol = X

X = 2.083/1 × 6.02 × 10^23

= 1.254 × 10^24 atoms

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3 years ago

Balance<br> _C2H6() +<br> O2(g) →

nignag [31]

Answer:

2C2H6 + 7O2 → 4 CO2 + 6H20

Explanation:

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3 years ago

Why critical thinking and skepticism are important to scientific inquiry

Ludmilka [50]

Inquiry; wanting to know. Thinking critically to figure out, understand. However being skeptic to not fall on one simple answer. For possibly, it could be incorrect.

6 0

4 years ago

Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of water is pro

Lubov Fominskaja [6]

This is an incomplete question, here is a complete question.

Aqueous sulfuric acid (H₂SO₄) reacts with solid sodium hydroxide (NaOH) to produce aqueous sodium sulfate (Na₂SO₄) and liquid water (H₂O) . If 12.5 g of water is produced from the reaction of 72.6 g of sulfuric acid and 77.0 g of sodium hydroxide, calculate the percent yield of water. Round your answer in significant figures.

Answer: The percent yield of water is, 46.8 %

Explanation : Given,

Mass of $H_2SO_4$ = 72.6 g

Mass of $NaOH$ = 77.0 g

Molar mass of $H_2SO_4$ = 98 g/mol

Molar mass of $NaOH$ = 40 g/mol

First we have to calculate the moles of $H_2SO_4$ and $NaOH$ .

$\text{Moles of }H_2SO_4=\frac{\text{Given mass }H_2SO_4}{\text{Molar mass }H_2SO_4}$

$\text{Moles of }H_2SO_4=\frac{72.6g}{98g/mol}=0.741mol$

and,

$\text{Moles of }NaOH=\frac{\text{Given mass }NaOH}{\text{Molar mass }NaOH}$

$\text{Moles of }NaOH=\frac{77.0g}{40g/mol}=1.925mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

From the balanced reaction we conclude that

As, 1 mole of $H_2SO_4$ react with 2 mole of $NaOH$

So, 0.741 moles of $H_2SO_4$ react with $0.741\times 2=1.482$ moles of $NaOH$

From this we conclude that, $NaOH$ is an excess reagent because the given moles are greater than the required moles and $H_2SO_4$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $H_2O$