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krok68 [10]
3 years ago
7

How mant low dose 81mg aspirin tablets can be made from 1.21 kg of aspirin​

Chemistry
1 answer:
KiRa [710]3 years ago
3 0

Answer:

14,938 tablets.

Explanation:

WE divide:

1.21 kg / 81 mg

1.21 kg = 1,210 g = 1.210,000 mg.

So it is 1,210,000 / 81

= 14,938 tablets.

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NEED HELP ASAPPP<br><br> What is the number of beryllium atoms in 78.0g of Be?
polet [3.4K]

Answer: number of atoms is 5.21 · 10^24

Explanation: Atomic mass of Be is 9.012 g/mol.

Number of moles n = m/M = 78.0 g / 9.012 g/mol =

Multiply this with Avogadro number Na = 6.022*10^23 1/mol

4 0
3 years ago
a car manufacturer claims that since their car engines dont get very hot, more of the gasolines energy can be used to make the c
ivanzaharov [21]
Newton’s 2nd law? Maybe I’m not completely sure
7 0
4 years ago
A 0.5438 g of a C.H.O. compound was combusted in air to make 1.039 g of CO2 and 0.6369 g H20. What is the empirical formula? Bal
goblinko [34]

Answer:

C₃H₅O₂

4C₃H₅O₂ + 13O₂ → 12CO₂ + 10H₂O

Explanation:

The reaction can be expressed as:

CₓHₓOₓ + nO₂ → CO₂ + H₂O

Under the assumption that there was a total combustion, all of the carbon in the reactant was combusted into CO₂, so <u>the mass of C contained in the C.H.O. compound is the same mass of C contained in 1.039 g of CO₂</u>:

1.039gCO_{2}*\frac{1molCO_{2}}{44gCO_{2}} *\frac{1molC}{1molCO_{2}} *\frac{12gC}{1molC} =0.2834gC

All of the hydrogens atoms in the compound ended up becoming H₂O, so <u>the mass of H contained in the C.H.O. compound is the same mass of H contained in 0.6369 g of H₂O</u>:

0.6369g*\frac{1molH_{2}O}{18gH_{2}O} *\frac{1molH}{1molH_{2}O} *\frac{1gH}{1molH} =0.0354gH

Because the compound is composed only by C, H and O, <u>the mass of O in the compound can be calculated by substraction</u>:

0.5438 g Compound - 0.2834 g C - 0.0354 g H = 0.2250 g O

In order to determine the empirical formula, we calculate the moles of each component:

  • mol C = 0.2834 g C ÷ 12 g/mol = 0.0236 mol C
  • mol H = 0.0354 g H ÷ 1 g/mol = 0.0354 mol H
  • mol O = 0.2250 g O ÷ 16 g/mol = 0.0141 mol O

Then we divide those values by the lowest one:

0.0236 mol C ÷ 0.0141 = 1.67

0.0354 mol H ÷ 0.0141 = 2.51

0.0141 mol O ÷ 0.0141 = 1

If we multiply those values by 2, we're left with the empirical formula C₃H₅O₂.

  • The reaction is:

4C₃H₅O₂ + 13O₂ → 12CO₂ + 10H₂O

8 0
3 years ago
A solution was made by dissolving 5.10 mg of hemoglobin in water to give a final volume of 1.00 ml. the osmotic pressure of this
Assoli18 [71]

The molecular weight of hemoglobin can be calculated using osmotic pressure

Osmotic pressure is a colligative property and it depends on molarity as

πV = nRT

where

π = osmotic pressure

V = volume = 1mL = 0.001 L

n = moles

R = gas constant = 0.0821 L atm / mol K

T = temperature = 25°C = 25 + 273 K = 298 K

Putting values we will get value of moles

moles=\frac{\pi V}{RT}=\frac{0.00195X0.001}{0.0821X298}mol

we know that

moles=\frac{mass}{molarmass}

Therefore

molarmass=\frac{mass}{moles}=\frac{5.10X10^{-3}g}{7.97X10^{-8}}=6.399X10^{4}g

5 0
3 years ago
Which has more mass, a mole of water (h2o) or a mole of glucose (c6h12o6)?
Semenov [28]
It is important to note that mass and mole pertain to different units of measurement, thus, 1 mole of one substance may have a lower or higher mass compared to a different substance. The mass of an object gives a measure of the number of atoms present in the substance while the number of moles of a substance refers to the amount of a chemical substance it has and is often used for chemical reactions. 

For this problem, we first get the molar mass of each substance:

Molar mass of H2O = 18.0153 g/mol
Molar mass of C6H12O6 = 180.1559 g/mol

We then convert each substance into units of mass (grams), where:

1 mol H20 x 18.0153 g/mol = 18.0153 g H20
1 mol C6H12O6 x 180.1559 g/mol = 180.1559 g C6H12O6

It was then determined that 1 mole of glucose has more mass than 1 mole of water. 
3 0
4 years ago
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