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mezya [45]
2 years ago
12

What is the mass of 4.56 moles of copper (ii) fluoride​

Chemistry
1 answer:
musickatia [10]2 years ago
7 0

Answer:

463.0 g.

Explanation:

  • We can use the following relation:

<em>n = mass/molar mass.</em>

where, n is the mass of copper(ii) fluoride​ (m = 4.56 mol),

mass of copper(ii) fluoride​ = ??? g.

molar mass of copper(ii) fluoride​ = 101.543 g/mol.

∴ mass of copper(ii) fluoride​ = (n)(molar mass) = (4.56 mol)(101.543 g/mol) = 463.0 g.

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Answer:

A. endothermic.

A. Yes, absorbed.

Explanation:

Let's consider the following thermochemical equation.

2 HgO(s) ⇒ 2 Hg(l) + O₂(g)  ΔH = 182 kJ

The enthalpy of the reaction is positive (ΔH > 0), which means that the reaction is endothermic.

182 kJ are absorbed when 2 moles of HgO react (molar mass 216.59 g/mol). The heat absorbed when 72.8 g of HgO react is:

72.8g.\frac{1mol}{216.59g} .\frac{182kJ}{2mol} =30.6kJ/mol

6 0
3 years ago
A car travels 10km in 10 min so what is the average
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Average speed in km/h:

S = D/T

T = 10/60 hrs
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3 years ago
How many moles of co2 can be produced by the complete reaction of 1.53 g of lithium carbonatewith excess hydrochloric acid (bala
nlexa [21]
Moles of Li2CO3 = 1.53/73.891 = 0.0207 mole
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A 16.0 mL sample of a 1.04 M potassium sulfate solution is mixed with 14.3 mL of a 0.880 M barium nitrate solution and this prec
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Number of moles in the K2SO4 sample
= (16/1000)*1.04= 0.01664 mol

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Since the reaction is a 1:1 ratio between the two reactants, the limiting reagent is the one containing a smaller number of moles, namely Ba(NO3)2.

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Actual yield = 2.60 g (given)
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Answer: 
1. the limiting reagent is Barium Nitrate (Ba(NO3)2)
2. the theoretical yield is 2.94 g
3. the percentage yield is 88.5%

I apologize for the mistake previous to this update.

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3 years ago
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