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nikdorinn [45]
4 years ago
9

A balloon has 18.9 moles of hydrogen gas at a volume of 428 L. What would the volume of the gas be if the balloon had 14.0 moles

of hydrogen gas left after 1 day?
Chemistry
1 answer:
den301095 [7]4 years ago
6 0

Answer:

V₂ = 317 L

Explanation:

Given data:

Initial number of moles of hydrogen = 18.9 mol

Initial volume of gas = 428 L

Final volume = ?

Final number of moles = 14.0 mol

Solution:

According to the Avogadro law,

Number of moles of gas is directly proportional to the volume of gas at constant temperature and pressure.

Mathematical expression:

V₁/n₁  =  V₂/n₂

V₁ = Initial Volume of balloon

n₁  = initial number of moles

V₂ = Final volume of balloon

n₂ = Final number of moles

Now we will put the values.

428 L / 18.9 mol =  V₂/ 14 mol

V₂ =428 L × 14 mol  / 18.9 mol

V₂ = 5992 L /18.9

V₂ = 317 L

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In each equation, label the acids, bases, and conjugate acid-base pairs. (Type your answer using the format [NO3]- for NO3-.)
Kamila [148]

Answer:

a) O²⁻ + H₂O <-----> OH⁻ + OH⁻

Acid = H₂O

Base = O²⁻

Conjugate Acid = OH⁻

Conjugate Base = OH⁻

b) HClO₄ + H₂SO₄ <-----> ClO₄⁻ + H₃SO₄⁺

Acid = HClO₄

Base = H₂SO₄

Conjugate Acid = H₃SO₄⁺

Conjugate Base = ClO₄⁻

c) NH₃ + HNO₃ <--> NH4⁺ + NO₃⁻

Acid = HNO₃

Base = NH₃

Conjugate Acid = NH4⁺

Conjugate Base = NO₃⁻

Explanation:

- Acids are molecules or ions capable of donating a proton (H⁺).

- Bases are molecules or ions that readily accept the H⁺ from acids.

- Conjugate Acids, according to the Brønsted–Lowry acid–base theory, are chemical compounds formed after the reception of a proton (H⁺) from an acid by a base.

- Conjugate Bases, Brønsted–Lowry acid–base theory, are the leftovers from when acids donate their proton (H⁺).

4 0
3 years ago
7.How would the number of moles (n) of O2 change if your atmospheric pressure was doubled and all other variables stayed the sam
goldenfox [79]

The number of moles (n) of O2 will be double if atmospheric pressure was doubled and all other variables stayed the same.

<h3>About Ideal gas Law</h3>

The general gas equation, often known as the ideal gas law, is the equation of state for a fictitious ideal gas. It has a number of limitations, but it provides a decent approximation of the behavior of numerous gases under various circumstances.

<h3>Explanation:</h3>

Applying the law of ideal gas: PV = nRT.

where,

P= pressure of the gas in the atm.

V= volume of the gas in L.

n = no. of moles of the gas in mol.

R = Universal gas constant,

T = temperature of the gas in K.

If V and T are constant and have different values of P and n:

(P₁n₂) = (P₂n₁).

P₂ = 2P₁,

∴ n₂ = (P₂n₁)/(P₁) = (2P₁n₁)/(P₁) = 2n₁.

therefore if we double the pressure then no. of the moles of O2 will be doubled.

Learn more about Pressure here:-

brainly.com/question/27533579

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6 0
2 years ago
How many grams of LiOH are produced from 9.89 g of Li?
Nonamiya [84]

Taking into account the stoichiometry of the reaction, 34.12 grams of LiOH are produced from 9.89 g of Li.

In first place, the balanced reaction is:

2 Li + 2 H₂O ⇒ 2 LiOH + H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Li= 2 moles
  • H₂O= 2 moles
  • LiOH= 2 moles
  • H₂= 1 mole

The molar mass of each compound is:

  • Li= 6.94 g/mole
  • H₂O= 18 g/mole
  • LiOH= 23.94 g/mole
  • H₂= 2 g/mole

By reaction stoichiometry, the following amounts of mass of each compound participate in the reaction:

  • Li= 2 moles× 6.94 g/mole= 13.88 g
  • H₂O= 2 moles× 18 g/mole= 36 g
  • LiOH= 2 moles× 23.94 g/mole= 47.88 g
  • H₂= 1 mole× 2 g/mole= 2 g

Then you can apply the following rule of three: if by reaction stoichiometry 13.88 g of Li produce 47.88 g of LiOH, 9.89 g of Li produce how much mass of LiOH?

mass of LiOH=\frac{9.89 g of Li*47.88 g of LiOH}{13.88 f of Li}

Solving:

<u><em>mass of LiOH= 34.12 grams</em></u>

Finalli, 34.12 grams of LiOH are produced from 9.89 g of Li.

Learn more:

  • brainly.com/question/19474065?referrer=searchResults
  • brainly.com/question/20703641?referrer=searchResults
7 0
3 years ago
The Himalaya mountain range stretches about 2,400 km from Tibet into Pakistan. It began forming when the Indian plate collided w
Tanya [424]
This immense mountain range began to form between 40 and 50 million years ago, when two large landmasses, India and Eurasia, driven by plate movement, collided. Because both these continental landmasses have about the same rock density, one plate could not be subducted under the other.Mar. 9, 2015
5 0
3 years ago
A 0.2 g sample of pyrolusite is analyzed for manganese content as follows. Add 50.0 mL of 0.1 M solution of ferrous ammonium sul
enyata [817]

Answer:

66.7%

Explanation:

The reaction for the titration of the excess ferrous ion is:

  • 5Fe⁺² + MnO₄⁻ + 8H⁺ → 5Fe³⁺ + Mn²⁺ + 4H₂O

We calculate the moles of Fe⁺² from the used moles of KMnO₄:

  • 0.02 M * 15.0 mL = 0.30 mmol KMnO₄
  • 0.3 mmol KMnO₄ * \frac{5mmolFe^{+2}}{1mmolKMnO_4} = 1.5 mmol Fe⁺²

Then we substract those 0.30 mmol from the original amount used:

  • 0.1 M * 50.0 mL = 5.0 mmol Fe⁺²
  • 5.0 - 1.5 = 3.5 mmol Fe⁺²

The reaction between ferrous ammonium sulfate and MnO₂ is:

  • 2Fe⁺² + MnO₂ + 4H⁺ → 2Fe³⁺ + Mn²⁺ + 2H₂O

So we convert those 3.5 mmol Fe⁺² that were used in this reaction to MnO₂ moles:

  • 3.5 mmol Fe⁺²  * \frac{1mmolMnO_2}{2mmolFe^{+2}}= 1.75 mmol MnO₂

Then we convert MnO₂ to Mn₃O₄, using the reaction:

  • 3MnO₂ → Mn₃O₄ + O₂
  • 1.75 mmol MnO₂ * \frac{1mmolMn_3O_4}{3mmolMnO_2} = 0.583 mmol Mn₃O₄

Finally we convert Mn₃O₄ moles to grams:

  • 0.583 mmol Mn₃O₄ * 228.82 mg/mmol = 133.40 mg Mn₃O₄

And calculate the percent

  • 0.2 g = 200 mg
  • 133.40 / 200 * 100% = 66.7%
5 0
3 years ago
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