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Sedbober [7]
3 years ago
6

HELP PWEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE!!!!

Mathematics
2 answers:
KIM [24]3 years ago
8 0

Answer:

Height = 22 Volume = 10890

Step-by-step explanation:

The width is 11 so multiply by 2 to get 22.

Then just do 45 x 11 x 22 which is 10890.

IgorC [24]3 years ago
4 0

Answer:

The height of the prism measures 22 meters

The volume of the prism measures 10,890 cubic meters.

Step-by-step explanation:

The height is twice the width of the prism.

The prism's width is 11 meters.

2 x 11 = 22

The volume of a rectangular prism is calculated as:

V = l x w x h

So, the volume is:

V = 45 x 11 x 22

The volume is 10,890 cubic meters.

Hope this helps!

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1.272 divided by 0.003?
icang [17]

Answer:

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Step-by-step explanation:

you need to use long divison to find the number <3

6 0
3 years ago
1=10^0 into logarithmic form
Tatiana [17]

Answer:

0 = log_{10} 1

Step-by-step explanation:

Base for the exponent and for the logarithm are the same!

10^0 is the <u>exponential</u> form where 10 is the base and 0 the exponent

log_{10} 1 is the l<u>ogarithm</u> form where 10 is the base

To solve log_{10} 1 =   ask the question :

To what power should I raise the base 10 to obtain the number 1 ?

The answer to the power 0 therefore

log_{10} 1 = 0

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7 0
3 years ago
How do I do this problem?
lyudmila [28]
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6 0
3 years ago
Who is good at algebra and is willing to help someone out with it-If so please help me I would really appreciate it
madam [21]

Answer:

4y = -x + 9

_______________________________

6 0
4 years ago
Determine the coordinates of the vertex for each quadratic function and whether the parabola has a maximum or minimum. 4. y = x²
GREYUIT [131]

Answer:

minimum, coordinates of vertex: (-3,-11)

explanation:

\sf y =x^2 +6x-2

x coordinates on vertex:

<u>solving steps</u>:

  • \sf \dfrac{-b}{2a}
  • \sf \dfrac{-6}{2(1)}
  • \sf -3

<u>Find y-coordinate on vertex:</u>

\sf y =x^2 +6x-2

\sf y =(-3)^2 +6(-3)-2

\sf y =-11

\mathrm{If}\:a < 0,\:\mathrm{then\:the\:vertex\:is\:a\:maximum\:value}

\mathrm{If}\:a > 0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}

coordinates: (-3,-11) thus minimum

6 0
3 years ago
Read 2 more answers
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