The duration of a flash from a camera is timed at 0.004 seconds accurate to 1 / 1000 of a second calculate the upper and lower b
ounds for the duration of the flash using in quality
1 answer:
Answer:
0.0035 ≤ x ≤ 0.0045
Step-by-step explanation:
Given that:
The error = 1/1000 = 0.001 / 2 = 0.0005 s
Hence, 0.004 ± Error
0.004 ± 0.0005
Lower boundary = (0.004 - 0.001) = 0.0035
Upper boundary = (0.004 + 0.001) = 0.0045
0.0035 ≤ x ≤ 0.0045
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Answer:
The answer to this is B.
Step-by-step explanation:
Anytime a number/variable is squared by a 0, it always equals a 1.
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~Shane
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