Question

The duration of a flash from a camera is timed at 0.004 seconds accurate to 1 / 1000 of a second calculate the upper and lower bounds for the duration of the flash using in quality
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Answer 1

Answer:

0.0035 ≤ x ≤ 0.0045

Step-by-step explanation:

Given that:

The error = 1/1000 = 0.001 / 2 = 0.0005 s

Hence, 0.004 ± Error

0.004 ± 0.0005

Lower boundary = (0.004 - 0.001) = 0.0035

Upper boundary = (0.004 + 0.001) = 0.0045

0.0035 ≤ x ≤ 0.0045