<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
</span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
</span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
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<span>I hope this helps! </span>
5x-7y=14
-5x -5x
^
Subtract 5x from both sides
-7y=-5x+14
Divide by -7 by all of the numbers
y=-5/7x-2
8.5
the tenth is the first digit behind the dot. 4 rounds down so the 5 stays a 5
Answer:
An odd number times an even number is always even
e.g 2 × 3 = 6
4 × 5 = 20
adding 1 to an even number makes it odd
6 + 1 = 7
20 + 1 = 21
hope this helps...
A cube because it has 6 faces/sides and 12 edges.
