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d1i1m1o1n [39]
2 years ago
12

The product of 13 and x is than 36

Mathematics
2 answers:
Karolina [17]2 years ago
5 0

Answer:

x is 23

Step-by-step explanation:

grandymaker [24]2 years ago
4 0
13•X = 36 ?
36/13= about 2.769

13•X < 36 ?
36/13= about 2.769
X<2.769

13•X > 36 ?
36/13= about 2.769
X>2.769

Product means multiplication, and the problem is tell you to find the product of 13 and x so you multiply 13 and X. I wasn’t sure what you meant by “is than 36” so I gave you three possible equations. But when a word problem says “is” it means “equals(=)”

I hope this helps.
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If a triangle has a height of 12 inches and a base of 5 inches, what's its area? A. 90 sq. in. B. 45 sq. in. C. 60 sq. in. D. 30
Vilka [71]

Answer:

D

Step-by-step explanation:

(12*5)/2= 30

4 0
3 years ago
Quadratic inequalities
lina2011 [118]
See picture for rough graph

7 0
3 years ago
Marcy and her sister watched a cartoon movie that was 2 hours and 18 minutes long. after the movie, they played a card game for
Dmitry_Shevchenko [17]

Answer:

1:24pm

Step-by-step explanation:

Couple of ways to solve this. Here is one method
Convert all times to minutes and find the total number of minutes they spent on all 3 activities. Then convert to hours and minutes and subtract from the end time of 5;28 to get the start time of all activities which is also the start time of watching the movie (first activity)

So time spent:

Movie: 2 hours 18 minutes = 2 * 60 + 18 = 120 + 18 = 138 minutes
Card game: 34 minutes
Soccer: 1 hour 12 minutes = 1 * 60 + 12 = 72 minutes

Total time spent = 138 + 34 + 72 = 244 minutes = 4 hours and 04 minutes

Subtract 4:04 from 5:28 to get 1:24pm

Check
Movie watch starts at 4:04, ends at 1:24 + 2:18 or 3:42pm
Card game starts at 3:42pm ends at 3:42+0:34 ==> 4:16pm
Soccer starts at 4:16pm ends at 4:16pm + 1:12 ==> 5;28pm

7 0
2 years ago
Which of the following equations have complex roots?
mestny [16]

Answer:

A

Step-by-step explanation:

Complex roots of quadratic functions occur when the <u>discriminant is negative</u>.

<u>Discriminant</u>

b^2-4ac\quad\textsf{when}\:\:ax^2+bx+c=0

Evaluate the discriminant of each of the given equations.

\textsf{A.} \quad 3x^2+2=0

\implies a=3, \quad b=0, \quad c=2

\implies b^2-4ac=0^2-4(3)(2)=-24

As -24 < 0 the equation will have complex roots.

\textsf{B.} \quad 2x^2+1=7x

\implies 2x^2-7x+1=0

\implies a=2, \quad b=-7, \quad c=1

\implies b^2-4ac= (-7)^2-4(2)(1)=41

As 41 > 0 the equation does not have complex roots.

\textsf{C.} \quad 3x^2-1=6x

\implies 3x^2-6x-1=0

\implies a=3, \quad b=-6, \quad c=-1

\implies b^2-4ac=(-6)^2-4(3)(-1)=48

As 48 > 0 the equation does not have complex roots.

\textsf{D.} \quad 2x^2-1=5x

\implies 2x^2-5x-1=0

\implies a=2, \quad b=-5, \quad c=-1

\implies b^2-4ac=(-5)^2-4(2)(-1)=33

As 33 > 0 the equation does not have complex roots.

Learn more about discriminants here:

brainly.com/question/27444516

brainly.com/question/27869538

Learn more about complex roots here:

brainly.com/question/26344541

6 0
2 years ago
Someone please help me with these. I forgot how to do these. Need within a hour
Pavlova-9 [17]

Answer: same

Step-by-step explanation:

3 0
2 years ago
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