Answer:
A
Step-by-step explanation:
Recall that the sum of an arithmetic series is given by:

Where <em>n</em> is the number of terms, <em>a</em> is the first term, and <em>x</em>_<em>n</em> is the last term.
We know that the initial term <em>a</em> is 13, the common difference is 7, and the total sum is 2613. Since we want to find the number of terms, we want to find <em>n</em>.
First, find the last term. Recall that the direct formula for an arithmetic sequence is given by:

Since the initial term is 13 and the common difference is 7:

Substitute:

We are given that the initial term is 13 and the sum is 2613. Substitute:

Solve for <em>n</em>. Multiply both sides by two and combine like terms:

Distribute:

Simplify:

Isolate the equation:

We can use the quadratic formula:

In this case, <em>a</em> = 7, <em>b</em> = 19, and <em>c</em> = -5226. Substitute:

Evaluate:

Evaluate for each case:

We can ignore the second solution since it is negative and non-natural.
Therefore, there are 26 terms in the arithmetic series.
Our answer is A.