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nevsk [136]
3 years ago
11

1 ÷ 7 pls help me hi)

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
4 0

Answer:

7 lol

Step-by-step explanation:

self explanatory-

but you divide 1 by 7 you get 7

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What is the mission

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What is anser in 0.75 :
lawyer [7]

Answer:

This is incomplete.

Step-by-step explanation:

Repost the question.

6 0
3 years ago
Among fatal plane crashes that occurred during the past 55 ​years, 415 were due to pilot​ error, 96 were due to other human​ err
azamat

Answer:

Relative frequency:

\text{Pilot error}=415/1370=0.30\\\\\text{Other human error}=96/1370=0.07\\\\\text{Weather}=169/1370=0.12\\\\\text{Mechanical problems}=622/1370=0.45\\\\\text{Sabotage}=68/1370=0.05\\\\

The most serious threat to aviation safety is, according to this data, "mechanical failures". It can be improved by more rigorous inspection and better maintenance policies and execution.

Step-by-step explanation:

We have the data for fatal plane crashes. The sum of plane crashes is

We can calculate the relative frequency as:

\text{Pilot error}=415/1370=0.30\\\\\text{Other human error}=96/1370=0.07\\\\\text{Weather}=169/1370=0.12\\\\\text{Mechanical problems}=622/1370=0.45\\\\\text{Sabotage}=68/1370=0.05\\\\

We can see that the most frequent cause is "mechanical problems", with a relative frequency of 0.45.

4 0
3 years ago
Reduce the fraction to lowest terms. 38x^2yz^2/ -19 yz^2z^3
Elenna [48]
Hope this is helpful.

3 0
4 years ago
The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 pounds,What perc
soldier1979 [14.2K]

Answer:

57.62% of players weigh between 180 and 220 pounds

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 200, \sigma = 25

What percent of players weigh between 180 and 220 pounds

We have to find the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 180.

X = 220

Z = \frac{X - \mu}{\sigma}

Z = \frac{220 - 200}{25}

Z = 0.8

Z = 0.8 has a pvalue of 0.7881

X = 180

Z = \frac{X - \mu}{\sigma}

Z = \frac{180 - 200}{25}

Z = -0.8

Z = -0.8 has a pvalue of 0.2119

0.7881 - 0.2119 = 0.5762

57.62% of players weigh between 180 and 220 pounds

4 0
3 years ago
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