All categories

3 years ago

10 POINTS!!!!!!GEOMETRY

Mathematics

1 answer:

Nimfa-mama [501]3 years ago

6 0

I need to know the answer to

You might be interested in

Factor the follow expression:

Olegator [25]

Answer:

2(4x-5)

Step-by-step explanation:

find the greatest common factor (biggest number that goes into 8 and 10)

it is two

divide both by two

put 2 on the outside to symbolize that you multiply the inside by 2

2(4x-5)

5 0

3 years ago

Read 2 more answers

Can someone help me with this please

Dmitriy789 [7]

for 7

Yes it is right cuz 16 is the double of 8 and even the price if doubled up so the price is right

for 8

Apply the formula

$2\sqrt{\frac{Area}{\pi } }$

$2\sqrt{\frac{154}{\pi } }$

$2\sqrt{49.02}$

$2(7)$

$14$

the diameter is 14

Hope this helps :)

7 0

3 years ago

2x + y = 8<br> -x - 3y = -12<br> Solve the above system of equations using substitution.

alina1380 [7]

I would solve for y on the top one and sub it into the bottom one.
y=-2x+8
(12/5, 16/5)

3 0

3 years ago

As the carbon content in steel increases, its ductility tends to decrease. A researcher at a steel company measures carbon conte

mixer [17]

Answer:

d. -5.666 to -0.926

Step-by-step explanation:

Here a pivotal quantity is $T = \frac{\hat{\beta_{1}}-\beta_{1}}{se(\hat{\beta_{1}})}$ where $\beta_{1}$ is the true slope of the regression equation (unknown), $\hat{\beta_{1}}$ is its least square estimate and $se(\hat{\beta_{1}})=1.097$ is its estimated standard error. And T has t-distribution with n-2=15-2=13 degrees of freedom (n is the sample size). We have that $\hat{\beta_{1}} = -3.30$ , and because we want the 95% confidence interval, we should use the 2.5th quantile of the t distribution with 13 df, this value is -2.16 and the 95% confidence intervale is given by $\hat{\beta_{1}}\pm t_{0.025}se(\hat{\beta_{1}})$ , i.e., $-3.30\pm (2.16)(1.097)$ . Therefore, the 95% confidence interval explicitly is (-5.666, -0.926)

6 0

4 years ago

How do you find a nonzero rational number closed under division

vredina [299]

For rational numbers to be closed under division, then any rational number divided by another rational number would have to be a rational number. This works for every rational number except when the second number is 0. Since division by 0 is undefined, dividing any rational number by the rational number zero will not give you a rational number. In order to make the rational numbers closed under division, you can choose any rational number you want except 0.

In other words, the set of rational numbers is not closed under division. The problem occurs only with division by zero. The set of rational numbers from which zero is removed is closed under division.

Every nonzero rational number is closed under division.

6 0

3 years ago