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4vir4ik [10]
2 years ago
5

Factor the denominator of the rational function y= 2x/x^2-16

Mathematics
1 answer:
lina2011 [118]2 years ago
8 0

x^2-16 factors to (x-4)(x+4)

You use the difference of squares rule here which is

a^2 - b^2 = (a-b)(a+b)

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<u><em>12 feet.
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<u><em /></u><em />4 1/2= 4.5 
<u><em /></u><u><em /></u><em />4 1/2+ 4= 9.5 + 2.5 = 12
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3 years ago
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What is the y value of the line when x = -1
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I cannot answer that question because I need to equation
6 0
3 years ago
600 can be written as 2 × b × co
NemiM [27]

Answer:

a = 3, b = 3, c = 5 and d = 2.

Step-by-step explanation:

The prime factorization of 600 is 2^3 * 3 * 5^2

3 0
2 years ago
An SRS of 350 high school seniors gained an average of x¯=21 points in their second attempt at the SAT Mathematics exam. Assume
Lynna [10]

Answer:

a) 21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

b) ME=2.58\frac{52}{\sqrt{350}}=7.17

c) ME=2.58\frac{52}{\sqrt{100}}=13.42

d) D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Part a

\bar X=21 represent the sample mean  

\mu population mean (variable of interest)  

\sigma=52 represent the population standard deviation  

n=350 represent the sample size  

99% confidence interval  

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58  

Now we have everything in order to replace into formula (1):  

21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

Part b

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{350}}=7.17

Part c

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{100}}=13.42

Part d

As we can see when we reduce the sample size we increase the margin of error so the best option for this case is:

D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

6 0
2 years ago
Which statement best describes the solution to this system of equations?
kondaur [170]

Answer:

x=-3

y=26

Step-by-step explanation:

3 0
3 years ago
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