can someone help me to solve this question. the questions is about to calculate the value of x . please help me thankyou
2 answers:
Answer:
Step-by-step explanation:
AC = AD So, Δ ACD is as isosceles triangle.
∠ADC ≅∠ACD = 63°
In ΔACD ,
63 + 63 + ∠DAC = 180 {Angle sum property of triangle}
126 + ∠DAC = 180
∠DAC = 180- 126
∠DAC = 54°
In ΔABC,
90+ 37 + ∠CAB = 180
127 + ∠CAB = 180
∠CAB = 180 - 127
∠CAB = 53
∠EAD + ∠DAC + ∠CAB = 180 {Straight line angles}
x + 54 + 53 = 180
x + 107 = 180
x = 180 -107
x = 73°
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Answer:
The cosine function to model the height of a water particle above and below the mean water line is h = 2·cos((π/30)·t)
Step-by-step explanation:
The cosine function equation is given as follows h = d + a·cos(b(x - c))
Where:
= Amplitude
2·π/b = The period
c = The phase shift
d = The vertical shift
h = Height of the function
x = The time duration of motion of the wave, t
The given data are;
The amplitude = 2 feet
Time for the wave to pass the dock
The number of times the wave passes a point in each cycle = 2 times
Therefore;
The time for each complete cycle = 2 × 30 seconds = 60 seconds
The time for each complete cycle = Period = 2·π/b = 60
b = π/30 =
Taking the phase shift as zero, (moving wave) and the vertical shift as zero (movement about the mean water line), we have
h = 0 + 2·cos(π/30(t - 0)) = 2·cos((π/30)·t)
The cosine function is h = 2·cos((π/30)·t).