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3 years ago

I NEED HELP ASAP 40points

Mathematics

1 answer:

kaheart [24]3 years ago

6 0

Answer:

5, 9 go in the boxes (left to right)

2 goes in second box on the bottom

Step-by-step explanation:

i dont what goes in the first bottom box

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. Trisha walked

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Answer:

Step-by-step explanation:

she walked for the first place in a while to be crying for a sec

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3 years ago

What is tan 330°? for algebra 2 with trig in it.

Alekssandra [29.7K]

Tan (330) = 0.133557

8 0

3 years ago

Point R is located at (1, 2) on a coordinate grid. Point S is located at (4, 5) on the same

Aleksandr-060686 [28]

Answer:

4.2 units

most likely answer choice B

Step-by-step explanation:

(1, 2) and (4, 5)

To find the distance between two points, we use the distance formula:

$d = \sqrt{(x_{2}-x_1)^2 + (y_2-y_1)^2 }$

Let's plug in what we know.

$d = \sqrt{(4 - 1)^2 + (5 - 2)^2 }$

Evaluate the parentheses.

$d = \sqrt{(3)^2 + (3)^2 }$

Evaluate the exponents.

$d = \sqrt{(9) + (9) }$

Add.

$d=\sqrt{18}$

Evaluate the radical.

d = 4.24

Round to the nearest tenth.

d = 4.2 units

*note: The answer choice is 4.6. I'm not sure if that is a typo on someone's end, but the distance between these two points is exactly 4.24264068712 units.

Hope this helps!

6 0

3 years ago

Convert y=9 from rectangular to polar form

Crazy boy [7]

Answer:

r = 9/sin Ф or r = 9 csc Ф

Step-by-step explanation:

The polar form is represented as:

x = r cos Ф and

y = r sin Ф

We are given:

y = 9

Putting value in y = r sin Ф

9 = r sin Ф

=> r = 9/sin Ф

1/sin Ф = csc Ф

or, r = 9 csc Ф

5 0

2 years ago

Read 2 more answers

The coordinates of the endpoints of ST are (-2,3) and (3, y) respectively supposethe distance between s and t us 13 units.What v

igor_vitrenko [27]

Answer:

The values of y would be -9 and 15

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$d=13\ units$

S(-2,3) and T(3,y)

substitute the given values in the formula and solve for y

$13=\sqrt{(y-3)^{2}+(3+2)^{2}}$

$13=\sqrt{(y-3)^{2}+25}$

squared both sides

$169=(y-3)^{2}+25$

$(y-3)^{2}=169-25$

$(y-3)^{2}=144$

take square root both sides

$y-3=(+/-)12$

$y=3(+/-)12$

$y=3(+)12=15$

$y=3(-)12=-9$

therefore

The values of y would be -9 and 15

5 0

3 years ago