What we know:
12 hour period from 8pm to 8am
temperature dropped from 8°F to 16°F from 8pm to 8am
We need to find temperature at 4 am.
We can start by setting up points:
8pm is are starting point with 8°F, we can express it as (0,8), 0 represents initial time from 0 to 12 hour span.
8am is the ending point with 16°F, we can express it as (12,16), 12 represents the end time of 0 to 12 hours span.
We will use these points to find slope.
slope=m=(16-8)/(12-0)=8/12=2/3
Now, we can set up an expression to find any temperature at a specific time. Aslo, x represents the hours not the the specific time of 4am. We will use 8 since 4am is the 8th hour of the 12 hour span. Using slope of 2/3 and the y intercept of (0,8) since we were already at 8°F at the initial time of 0 we have the function:
f(x)=2/3x+8
f(8)=2/3(8)+8= 40/3≈13.3°
Answer:
cos(52°) = 18/x
x = 18·sec(52°)
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you that ...
Cos = Adjacent/Hypotenuse
In this geometry, that means ...
cos(52°) = 18/x
You can use the relation sec(x) = 1/cos(x) to rewrite this as ...
x = 18·sec(52°)
_____
You can also use the complementary angle and the complementary trig function.
sin(90° -52°) = 18/x
Answer:
Answer:
Distance is 13.6 units.
Which means it is 13
Step-by-step explanation:
Given a grid shows the positions of subway stop and house. The subway stop is located at (-7, 8) and house is located at (6, 4).
we have to find the distance between house and the subway stop.
Points are (-7, 8) and (6, 4).
Using distance formula,
D= /(x2-x1)^2+(y2-y1)^2} = (6-(-7))^2+(4-8)^2=(13)^2+16}={169+16}={185}=13.60147\sim13.6units.
Hence, distance between house and the subway stop is 13.6 units.
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Answer:
y= 8
Step-by-step explanation:
In a Triangle we know,
W+Y+X=180 degree
then,
(180-52)+(4y-4)+3y=180
or, 128+4y-4+3y= 180
or, 7y= 180- 124
or, y= 56/7
or, y= 8
hope you got it.
