No it doesn't. The density of a gas depends on the temperature that is found. If it's hot the density reduces since its molecules spread, while at cold temperatures the density rises.
A spontaneous flow of thermal energy takes place from hot to cold. In order to flow thermal energy from a colder object to a hotter object, the work has to be implied on the system. The particle at higher temperature exhibits more kinetic energy in comparison to the particle at a lower temperature. Thus, there is a continuous flow of heat between the objects from the higher temperature to the lower temperature.
In order to balance the chemical equation, you need to make sure the number of atoms of each element on the reactant side is equal to the number of atoms of each element on the product side. In order make both sides equal, you will need to multiply the number of atoms in each element until both sides are equal
To figure out the ratios of these compounds, it is important to remember that the charge of these compounds must be <em>
neutral</em>.
So in order to make them neutral, you must have specific ratios:
; This is true because they both have a charge of magnitude of 1.
; We need 3 chlorine atoms because we need to balance out the charge from the 3+ charge of aluminum - therefore since chlorine has a 1- charge, we need 3 atoms.
; The charges of the magnesium (2+) are balanced with the oxygen charge (2-).
; This is correct because if charges are like this, you must find the least common factor in order to know the ratio. The LCF is 6, therefore, for the atom with a 3+ charge, you need 2 of them, and for the atom with a 2- charge, you need 3 of them. This keeps the charge neutral.
Answer:
6.72M of HNO3
Explanation:
In the problem you are diluting the original HNO3 solution by the addition of some water. The final volume is:
290.7mL + 350.0mL = 640.7mL
And you are diluting the solution:
640.7mL / 350.0mL = 1.8306 times
As the original concentration was 12.3M, the final concentration will be:
12.3M / 1.8306 =
<h3>6.72M of HNO3</h3>
