What is the balance equation for HgO(s)- Hg(l)+O2(g)

How many moles are there in 24.00 g of NaCl

Elis [28]

Answer:

The answer to your question is 0.41 moles

Explanation:

Data

moles of NaCl = ?

mass of NaCl = 24 g

Process

To solve this problem just calculate the molar mass of NaCl, and remember that the molar mass of any substance equals to 1 mol.

1.- Calculate the molar mass

NaCl = 23 + 35.5 = 58.5 g

2.- Use proportions and cross multiplication

58.5 g of NaCl ------------------- 1 mol

24.0 g ------------------- x

x = (24 x 1) / 58.5

x = 0.41 moles

6 0

3 years ago

Which element has a gas notation of [Kr]5s2 4d7

Olenka [21]

I think it would be Kriptonite

7 0

3 years ago

Which equation represents the correct net ionic equation for the reaction between Ca(OH)2 and H2SO4?

Georgia [21]

<u>Answer:</u> The correct net ionic equation for the reaction is $2H^{+}(aq)+2OH^{-}(aq)\rightarrow 2H_2O(l)$

<u>Explanation:</u>

Net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.

The balanced molecular equation is:

$Ca(OH)_2(aq)+H_2SO_4(aq)\rightarrow CaSO_4(aq)+2H_2O(l)$

The complete ionic equation follows:

$Ca^{2+}(aq)+2OH^-(aq)+2H^+(aq)+SO_4^{2-}(aq)\rightarrow 2Ca^{2+}(aq)+SO_4^{2-}(aq)+H_2O(l)$

As calcium and sulfate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

$2H^{+}(aq)+2OH^{-}(aq)\rightarrow 2H_2O(l)$

Hence, the correct net ionic equation for the reaction is $2H^{+}(aq)+2OH^{-}(aq)\rightarrow 2H_2O(l)$

7 0

3 years ago

Research online to find out what the acidity of the rainfall is where you live. If you live in an area which is affected by acid

In-s [12.5K]

Answer & Explanation: Acid rain occurs when sulfur dioxide and nitrogen oxide are released into the air to create a chemical reaction. When the two mix in the air (oxygen), they will get into the water and mix with other pollutants in the air, making acid rain.

3 0

3 years ago

How many kilograms of oxygen did Samantha need to utilize to react with 36.29 kg of triglycerides (C55H104O6)?

Paraphin [41]

Answer:

105.33Kg of O2.

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

C55H104O6 + 78O2 —> 55CO2 + 52H2O

Step 2:

Determination of the masses of C55H104O6 and O2 that reacted from the balanced equation.

This is illustrated below:

Molar mass of C55H104O6 = (12x55) + (104x1) + (16x6) = 860g/mol

Mass of C55H104O6 from the balanced equation = 1 x 860 = 860g.

Divide the mass of C55H104O6 by 1000 to express in kg i.e

Mass of C55H104O6 = 860/1000= 0.86Kg

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 78 x 32 = 2496g.

Divide the mass of O2 by 1000 to express in kg i.e

Mass of O2 = 2496/1000 = 2.496kg.

From the balanced equation above,

0.86kg of C55H104O6 reacted with 2.496Kg of O2.

Step 3:

Determination of the mass of O2 in kg needed to react with 36.29 kg of triglycerides (C55H104O6).

This can be obtained as follow:

From the balanced equation above,

0.86kg of C55H104O6 reacted with 2.496Kg of O2.

Therefore, 36.29 kg of C55H104O6 will react with = (36.29 x 2.496)/0.86 = 105.33Kg of O2.

Therefore, 105.33Kg of O2 is needed for the reaction.

5 0

3 years ago