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3 years ago

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if alpha and beta are zeroes of polynomial 4x^2-1 obtain a quadratic polynomial whose zeroes are 1/2 alpha+beta and 1/alpha+2 be

ta

1 answer:

AysviL [449]3 years ago

4 0

Ok so 4x2-1 gives us 3

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Your cousin wants to buy a coat and can spend at most $95. He has a coupon for $20 off any coat. Write an inequality to find the

insens350 [35]

Answer:

Step-by-step explanation:

Your cousin wants to buy a coat and can spend at most $95. This means that the total amount of money that he can spend in buying the coat would be lesser than or equal to $95.

He has a coupon for $20 off any coat. Let x represent the cost of the coat. The amount that he can pay for the coat will be x - 20.

The inequality to find the original prices of coats he can afford would be

x - 20 lesser than or equal to 95

8 0

3 years ago

What statements must be true of an equation before you can use quadratic formula?

Alexus [3.1K]

Before you use the quadratic formula, you have to make sure the equation itself is a quadratic and that a and b are not 0.

3 0

3 years ago

Please answer I need help quick!!!

grigory [225]

Answer:

85

Step-by-step explanation:

Place the 9 in for X and 9 to the second power is 81. Then add 4...85.

4 0

3 years ago

Read 2 more answers

If a production line produces 50 mouse traps every 30 minutes over the course of a 10 hour work day with a half-hour break for l

stira [4]

The awnser is 1000 because 60 miutes in an hour, 50 mouse traps every half hour so 100 mouse traps an hour multiply that by 10 and you get 1000, i think.

4 0

4 years ago

Read 2 more answers

write a function g whose graph represents a translation 2 units to the right followed by a horizontal stretch by a factor or 2 o

Alenkinab [10]

$\bf f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}\\\\
f(x)=&{{ A}} \left|{{ B }}x+{{ C}} \right|+{{ D}}
\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see,

$\bf f(x)=|x| \implies \begin{array}{lllccll}
f(x)=&1|&1x&+0|&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.

the smaller A is, the wider it opens, the larger it is, the more it shrinks.

5 0

3 years ago