Question

Given that A varies directly as B and inversely as C and that; A=12 when B=3 and C=2. Find B when A=10 and C=1.5​

Answer 1

Answer:

1.9

Step-by-step explanation:

The above is direct and inverse variation.

A = kB/C -----------(1)

A=12

B = 3

C= 2

substitute A, B and C into equation (1).

12 = K × 3/2

12 = 3k/2

12×2 = 3k

3K = 24

dividing bothsides by 3

3K/3 = 24/3

K = 8

substitute K = 8 into equation (1)

A = 8B /C --------------(2)

Equation (2) is the equation connecting

A,B and C.

Finding B when A = 10 and C = 1.5

10 = 8B / 1.5

10× 1.5 = 8B

15 = 8B

Dividing bothsides by 8 :

B = 15/8

B = 1.875

B = 1. 9 ( approximately)