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2 years ago

What is the period of the graph of y = 5 sin (pi x) + 3?

Mathematics

1 answer:

Natasha2012 [34]2 years ago

7 0

Equate whats inside (arguments) $\sin$ with base period of sine function $2\pi$ and solve for x to get period,

$\pi x=2\pi\implies x=2$

So the period of the graph of the given function is precisely 2.

Hope this helps :)

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Multiply 6/5 x 25/2 PLEASE HURRY I NEED IT NOW

FromTheMoon [43]

Answer:

Step-by-step explanation:

65×252=?

For fraction multiplication, multiply the numerators and then multiply the denominators to get

6×255×2=15010

Since 150 divided by 10 equals 15 then,

15010=15

Therefore:

65×252=15

6 0

2 years ago

Read 2 more answers

consider the line y= 2/3x-0. Find the equation of the line that is parallel to this line and passes through the point (8, 4).

tresset_1 [31]

Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)

slope intercept form :
y=m+b

m=slope

If the line is parallel to y=2/3 x-0, the line will have the same slope, therefore the slope will be: 2/3.

Data:
(8,4)
m=2/3

y-y₀=m(x-x₀)
y-4=2/3(x-8)
y-4=2/3 x-16/3
y=2/3 x-16/3+4
y=2/3 x-4/3 (slope intercept form)

Answer: The equation of the line would be: y=2/3 x-4/3.

if we have the next slope "m",then the perendicular slope will be:
m´=-1/m

We have this equation: y=2/3 x+0; the slope is: m=2/3.

The perpendicular slope will be: m`=-1/(2/3)=-3/2

And the equation of the perpendicular line to : y=2/3 x+0, given the point (8,4) will be:

y-y₀=m(x-x₀)
y-4=-3/2 (x-8)
y-4=-3/2 x+12
y=-3/2x + 12+4
y=-3/2x+16

answer: the perpendicular line to y=2/3 x+0 , given the point (8,4) will be:
y=-3/2 x+16

3 0

2 years ago

What is the absolute value of |6|

motikmotik

Answer:

Step-by-step explanation:

7 0

2 years ago

A environmental initiative has the goal of saving at least 25 2525 million hectares of rainforest through both planting trees an

Anestetic [448]

Answer:

The possible way for the initiative to accomplish its goal without exceeding its budget is use 12.5 hectares for planting trees and 12.5 hectares by purchasing land.

Step-by-step explanation:

Let the variable X represent the amount of land used for planting trees and Y represent the amount of land purchased.

The goal of the environmental initiative is to save at least 25 million hectares of rain forest.

That is:

X + Y = 25....(i)

Now it is provided that:

The cost of planting trees is $ 400 per hectare.
The cost of purchasing land is $ 260 per hectare.
The initiative has a budget of $8,250 million.

Using the above data it can be said that:

400X + 260Y = 8250....(ii)

Solve equations (i) and (ii) simultaneously.

$\ \ \ \ x+y=25]\times 260\\400x+260y=8250\\\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\\\\\Rightarrow\\\\260x+260y=6500\\400x+260y=8250\\(-)\_\_\_\_\_\ (-)\_\_\_\_(-)\_\_\_\\\\\Rightarrow\\\\-140x=-1750\\\\x=\frac{1750}{140}\\\\x=12.5$

Then the value of y is:

$x+y=25\\y=25-x\\y=25-12.5\\y=12.5$

Thus, the possible way for the initiative to accomplish its goal without exceeding its budget is use 12.5 hectares for planting trees and 12.5 hectares for purchasing land.

4 0

2 years ago

If a(9,18) and b(1,12) find

galina1969 [7]

$AB= \sqrt{(9-1)^2+(18-12)^2} = \sqrt{8^2+6^2}= \sqrt{64+36} = \sqrt{100}=10$

6 0

3 years ago