Answer:
31.4 in³
Step-by-step explanation:
The box is just big enough to hold the 3 balls, so it must have a length 6 times the radius of each ball, a width 2 times the radius, and a height 2 times the radius.
The volume of the box is:
V = (6r)(2r)(2r)
V = 24r³
The volume of the 3 balls is:
V = 3 (4/3 π r³)
V = 4πr³
So the volume of the air is:
V = 24r³ − 4πr³
V = (24 − 4π) r³
Since r = 1.4 inches:
V = (24 − 4π) (1.4 in)³
V ≈ 31.4 in³
Answer ran 2 3/4 miles in 1/3 of an hour
2 3/4 miles =11/4 miles in 1/3 of hour
11/4 miles divided by 1/3 hr
11/4 ÷ 1/3
11/4 * 3/1 =33/4 =8 1/4 miles in 1 hr
Answer:
Step-by-step explanation:
<u>Given</u>
- Q(s) = -4s^3 + 7s^2 - 24;
- s = -4 and 1
<u>Verifying zeroes</u>
Q(-4) =
- -4(-4)^3 + 7(-4)^2 - 24 =
- 256 + 112 - 24 =
- 344
- Incorrect as 344 ≠ 0
Q(1) =
- -4(1)^3 + 7(1)^2 - 24 =
- -12 + 7 - 24 =
- -29
- Incorrect as -29 ≠ 0
Answer:
B
Step-by-step explanation:
Note the common difference between consecutive terms of the sequence.
d = 16 - 12 = 20 - 16 = 4
This indicates the sequence is arithmetic with sum to n terms
= 
[2a₁ + (n - 1)d ]
where a₁ is the first term and d the common difference
Here a₁ = 12 and d = 4, thus
= 
[ (2 × 12) + (41 × 4) ]
= 21( 24 + 164) = 21 × 188 = 3948 → B
Answer :
F-1(x)=-x/4-7/4
This is right
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