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3 years ago

This Is challenging I hope you can figure it out

Mathematics

1 answer:

max2010maxim [7]3 years ago

3 0

Answer:

980 hers your proof so 170 * 7 =180

Step-by-step explanation:

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Look at the picture please don’t guess

Grace [21]

Answer:5,6

Step-by-step explanation:

4 0

3 years ago

The markup of an MP3 player is $207.20. The markup rate is 60%. What is the cost?

ch4aika [34]

If markup is 60% of the cost, you have

... markup = 0.60×cost

... markup/0.60 = cost

... $207.20/0.60 = cost = $345.33

_____

If markup is 60% of the selling price, the other 40% is the cost. So, the cost is 40/60 = 2/3 of the markup.

... cost = (2/3)×markup = (2/3)×$207.20

... cost = $138.13

_____

Markup can be specified in terms of either selling price or cost. Those are the usual reference values; there could be others. When only the percentage is given, you don't have enough information to work the problem. You need to know what it is a percentage of. (Example problems in your text may tell you the expected interpretation.)

5 0

3 years ago

Write an equation in slope intercept form that represents the line shown?

Wittaler [7]

Answer:

I think the answer would be Y=-2X+5

Hope it helps you *^*

8 0

3 years ago

In quadrilateral QRST, . Is QRST a rectangle?

muminat

Is there a picture with it?

8 0

3 years ago

Sarah would like to make a 6 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of a mixture that is 80%

ivolga24 [154]

Answer:

a. The system of equations that models the situation is....

$0.80x+0.50y=3.60\\\\ 0.20x+0.50y=2.40$

b. The solution to the system: x = 2 and y = 4

The amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.

Step-by-step explanation:

Suppose, the amount of 80/20 mixture is $x$ pounds and the amount of 50/50 mixture is $y$ pounds.

So, the amount of peanuts in 80/20 mixture $= 0.80x$ pound and the amount of almonds in 80/20 mixture $=0.20x$ pound.

And the amount of peanuts in 50/50 mixture $=0.50y$ pound and the amount of almonds in 50/50 mixture $=0.50y$ pound.

Now, Sarah would like to make a 6 pounds nut mixture that is 60% peanuts and 40% almonds.

So, the amount of peanuts in that mixture $=(6\times 0.60)=3.60$ pounds

and the amount of almonds in that mixture $=(6 \times 0.40)= 2.40$ pounds.

So, the system of equations will be.........

$0.80x+0.50y=3.60 ...................(1)\\\\ 0.20x+0.50y=2.40...................(2)$

Subtracting equation (2) from equation (1), we will get.....

$(0.80x+0.50y)-(0.20x+0.50y)=3.60-2.40\\ \\ 0.60x=1.20\\ \\ x= \frac{1.20}{0.60}=2$

Now, plugging this $x=2$ into equation (1), we will get......

$0.80(2)+0.50y=3.60\\ \\ 1.60+0.50y=3.60\\ \\ 0.50y=3.60-1.60=2\\ \\ y=\frac{2}{0.50}=4$

So, the amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.

7 0

3 years ago