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A water tank is in the shape of a right rectangular prism. Its dimensions are 6 feet by 4 feet by 7 feet. What is the surface ar

Norma-Jean [14]

Answer:

$\LARGE{ \underline{\underline{ \sf{\pink{ Required\: answer:}}}}}$

<h2>GIVEN - </h2>

Water tank which is in a shape of right rectangular prism

Dimensions = 6 feet × 4 feet × 7 feet

Surface area of tank

<h2>SOLUTION - </h2>

Using formula of surface area of right rectangular prism -

Surface area =

$2(wl + hl + hw)$

L = length

w = width

h = height

( assumimg 6 feet = L , 4 feet = W , 7 feet = h)

Putting value of L, W and H in the equation. we get,

=2(4 × 6 + 7 × 6 + 7× 4)

= 2(24 + 42 + 28)

= 2( 94)

= 2 × 94

= 188

7 0

3 years ago

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Find three consecutive integers such that that product of the first and third is one

Tema [17]

Answer:

n = the first

n + 1 = the 2nd

n + 2 = the 3rd

n(n + 2) - (n + 1) = 10(n + 2) + 1

n2 + 2n - n - 1 = 10n + 20 + 1

n2 - 9n - 22 = 0

(n - 11)(n + 2) = 0

If two factors = 0, at least one must = 0.

n - 11 = 0

n = 11

11,12,13

n + 2 = 0

n = -2

-2,-1,0

7 0

3 years ago

(A) A small business ships homemade candies to anywhere in the world. Suppose a random sample of 16 orders is selected and each

Leviafan [203]

Following are the solution parts for the given question:

For question A:

$\to (n) = 16$

$\to (\bar{X}) = 410$

$\to (\sigma) = 40$

In the given question, we calculate $90\%$ of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

$\to \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{S}{\sqrt{n}}$

$\to C.I= 0.90\\\\\to (\alpha) = 1 - 0.90 = 0.10\\\\ \to \frac{\alpha}{2} = \frac{0.10}{2} = 0.05\\\\ \to (df) = n-1 = 16-1 = 15\\\\$

Using the t table we calculate $t_{ \frac{\alpha}{2}} = 1.753$ When $90\%$ of the confidence interval:

$\to 410 \pm 1.753 \times \frac{40}{\sqrt{16}}\\\\ \to 410 \pm 17.53\\\\ \to392.47 < \mu < 427.53$

So $90\%$ confidence interval for the mean weight of shipped homemade candies is between $392.47\ \ and\ \ 427.53$ .

For question B:

$\to (n) = 500$

$\to (X) = 155$

$\to (p') = \frac{X}{n} = \frac{155}{500} = 0.31$

Here we need to calculate $90\%$ confidence interval for the true proportion of all college students who own a car which can be calculated as

$\to p' \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{p'(1-p')}{n}}$

$\to C.I= 0.90$

$\to (\alpha) = 0.10$

$\to \frac{\alpha}{2} = 0.05$

Using the Z-table we found $Z_{\frac{\alpha}{2}} = 1.645$

therefore $90\%$ the confidence interval for the genuine proportion of college students who possess a car is

$\to 0.31 \pm 1.645\times \sqrt{\frac{0.31\times (1-0.31)}{500}}\\\\ \to 0.31 \pm 0.034\\\\ \to 0.276 < p < 0.344$

So $90\%$ the confidence interval for the genuine proportion of college students who possess a car is between $0.28 \ and\ 0.34.$

For question C:

In question A, We are $90\%$ certain that the weight of supplied homemade candies is between 392.47 grams and 427.53 grams.
In question B, We are $90\%$ positive that the true percentage of college students who possess a car is between 0.28 and 0.34.

Learn more about confidence intervals:

brainly.in/question/16329412

7 0

2 years ago

Jayce and Rylee are selling candy bars for a school fund raiser. Rylee sold 84 candy bars and raised $210. If Jayce raised $70 h

SOVA2 [1]

Jayce sold 28 bc $210/84 bars = $2.50 per bar. $70/2.50 = 28 bars

7 0

2 years ago

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What is the value of x? Enter your answer in the box. x =

Nikitich [7]

You are given that all three sides are equal. You also know that all three angles are also equal. Therefore since all three angles are equal and every triangle has 180 degrees, each angle is 180/3 = 60

So

7x - 3 = 60 Add three to both sides

7x - 3 + 3 = 60 + 3 Combine

7x = 63 Divide by 7

7x/7 = 63/7

x = 9 And that's your answer.

3 0

3 years ago