To calculate the frequency of the heterozygote genotype (Pq) for this gene we must use the Hardy-Weinberg equation ( p2 + 2pq + q2 = 1 ). This equation relies on the Hardy-Weinberg principle, a model in population genetics that states that the frequency of the alleles in a population is never changing, only the combinations (the genotypes) are changing.
If there are only two alleles (variations) of this gene in a population, then their frequencies should add up to 1 (100%). From this, we can calculate the frequency of the q allele.
p +q=1
0,3 +q=1
q= 1-0,3
q= 0,7
Now hat we have the frequency of the q allele we can use the HW equation to calculate the frequency of the heterozygotes.


0,09 + 2pq +0.49= 1
2pq +0,58= 1
2pq= 1-0.58
2pq=0,42
The freqency of the heterozygotes in this population is 0.42
Solution:
The genetic material dna consists of basic subunits called Nucleotides.
Nucleotides are the subunits of DNA. The four nucleotides are adenine, cytosine, guanine and thymine.
The nucleotide sequence of the DNA is GACT or RNA, which is the molecule. Hope this helps :)
The answers are yeast and penicillium.
Some yeasts are used in medicine, for example, some Saccharomyces species, Candida species, etc. They are used for the production of some amino acids, vitamins (C, B2), some proteins (insulin). Penicillium is used for production of antibiotics.