Answer:
20 K
Explanation:
It is given that,
The change in temperature is 20 C.
We need to find the change in thermodynamic temperature.
If teperauture T₁ = 0° C = 0+273 = 273 K
T₂ = 20° C = 20 + 273 = 293 K
The change in temperature,

So, the change in temperature of 20°C is equivalent to 20 K.
Answer:
The electric potential of the uniformly charge disk is 1392.1 V
Explanation:
Electric potential, for a uniformly charged disk at a distance A, is given as;
![V = \frac{\sigma}{2 \epsilon} [\sqrt{A^2 +R^2} -A]](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B%5Csigma%7D%7B2%20%5Cepsilon%7D%20%5B%5Csqrt%7BA%5E2%20%2BR%5E2%7D%20-A%5D)
Where;
σ is the charge density = 1.40 μC/m³
ε is the permittivity of free space = 8.85 x 10⁻¹²
A is the distance above the disk = 40 cm = 0.4 m
R is the radius of the disk = 0.12 m
Substitute in these values into the equation above, we will have
![V = \frac{1.4 X 10^{-6}}{2X8,85X10^{-12}}[\sqrt{0.4^2 +0.12^2}-0.4] \\\\V = (79096.05)(0.0176) = 1392.1 V](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1.4%20X%2010%5E%7B-6%7D%7D%7B2X8%2C85X10%5E%7B-12%7D%7D%5B%5Csqrt%7B0.4%5E2%20%2B0.12%5E2%7D-0.4%5D%20%5C%5C%5C%5CV%20%3D%20%2879096.05%29%280.0176%29%20%3D%201392.1%20V)
Therefore, the electric potential of the uniformly charge disk is 1392.1 V
From among the choices provided, the more appropriate
answer is ' T ', the initial letter often used to represent
words that include 'true', 'truth', 'trust', etc., (as well as
'tree', 'train', 'transmit', 'Transylvania', 'trachea', 'travesty',
and 'trick', which are irrelevant to the present discussion).
This response is the most fitting and appropriate, because
the statement that precedes the list of allowable choices is
exemplary in its accuracy and veracity. An ion can, in fact,
have a positive or negative charge, although the same ion
cannot have both.
Answer: The piezoelectric effect describes the property of certain solids to generate an electrical charge under mechanical stress. The actuating force modifies the microscopic structure of the body; dipoles are created between which a voltage builds up. And Their positive and negative charges complement each other creating two types of electricity: static electricity
Explanation:
Answer:
Electric flux;
Φ = 30.095 × 10⁴ N.m²/C
Explanation:
We are given;
Charge on plate; q = 17 µC = 17 × 10^(-6) C
Area of the plates; A_p = 180 cm² = 180 × 10^(-4) m²
Angle between the normal of the area and electric field; θ = 4°
Radius;r = 3 cm = 3 × 10^(-2) m = 0.03 m
Permittivity of free space;ε_o = 8.85 × 10^(-12) C²/N.m²
The charge density on the plate is given by the formula;
σ = q/A_p
Thus;
σ = (17 × 10^(-6))/(180 × 10^(-4))
σ = 0.944 × 10^(-3) C/m²
Also, the electric field is given by the formula;
E = σ/ε_o
E = (0.944 × 10^(-3))/(8.85 × 10^(-12))
E = 1.067 × 10^(8) N/C
Now, the formula for electric flux for uniform electric field is given as;
Φ = EAcos θ
Where A = πr² = π × 0.03² = 9π × 10^(-4) m²
Thus;
Φ = 1.067 × 10^(8) × 9π × 10^(-4) × cos 4
Φ = 30.095 × 10⁴ N.m²/C