Question

A 50-g chunk of 80 degrees C iron is dropped into a cavity in a very large block of ice at 0 degrees C. Show that 5.5 g of ice will melt. (The specific heat capacity of iron is 0.11 cal / (g * degree C)).

Answer 1

Answer:

5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity

Explanation:

The concept to solve this problem is given by Energy Transferred, the equation is given by,

$Q = mc\Delta T$

Where,

Q= Energy transferred

m = mass of water

c = specific heat capacity

$\Delta T =$ Temperature change (K or °C)

Replacing the values where mass is 50g and temperature is 80°C to 0°C we have,

$Q = mc\Delta T$

$Q = 50*0.11*(80-0)$

$Q = 440cal$

Then we can calculate the heat absorbed by m grams of ice at 0°C, then

$Q_2 = mL = 80*m$

How Q_1=Q_2, so

$80m=440$

$m=\frac{440}{80}$

$m = 5.5g$

Then 5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity