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3 years ago

HELPPP ASAAPPPPPPPPPPP this is in my test

Mathematics

1 answer:

posledela3 years ago

8 0

Answer:

B. 2,400

D. 240

F. 16

Step-by-step explanation:

362×8

1. 36(2)×(8) = 16

2. 3(6)2×(8)=480 (add 0 at the end since it's tens)

3. (3)62×(8)=2400 (add two 0 at the end since it's hundreds)

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(3 points) Buchtal, a manufacturer of ceramic tiles, reports on average 3.1 job-related accidents per year. Accident categories

Strike441 [17]

Answer:

0.8743 = 87.43% probability that more than one accident occurs per year

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Buchtal, a manufacturer of ceramic tiles, reports on average 3.1 job-related accidents per year.

This means that $\mu = 3.1$

What is the probability that more than one accident occurs per year?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

Then

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-3.6}*(3.6)^{0}}{(0)!} = 0.0273$

$P(X = 1) = \frac{e^{-3.6}*(3.6)^{1}}{(1)!} = 0.0984$

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0273 + 0.0984 = 0.1257$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.1257 = 0.8743$

0.8743 = 87.43% probability that more than one accident occurs per year

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