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2 years ago

The dropping off of sediments in a new place is called

2 answers:

7 0

The movement of sediments by wind, water, ice, or gravity is called erosion. Sediments are dropped in a new location. The process of dropping sediments in a new location is called deposition.

Anni [7]2 years ago

4 0

The movement of sediments by wind, water, ice, or gravity is called erosion. Sediments are dropped in a new location. The process of dropping sediments in a new location is called deposition. Some of the small pieces are deposited on the ocean floor

Hope that helps :)

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Which of the following is the best reference for more information regarding compounding?

stiks02 [169]

Compounding Corner on RxNet is the best reference for more information regarding compounding

Explanation:

RxNet is an open online community, consolidating scientists from the domains of chemistry, biochemistry and expanding industry of drug innovation and improvement. Compounding presents an innovative way for pharmacists to customize prescriptions to suit the requirements of their patients.

The art of compounding employs advanced medicine while still sticking to the roots of the profession of pharmacy. Compounding pharmacies can create unparalleled dosage forms based on patient preferences. Compounded medicines are usually reliable and sufficient for most victims who have spoken to their physician about their wellness.

6 0

3 years ago

On the window sill is a potted plant. The plant always seems to lean toward the window. Even though you turn its pot around ever

ICE Princess25 [194]

Answer:

because im trynna get these 5 points

Explanation:

mklnk.m

3 0

2 years ago

Damm [24]

Answer: the answer is 18

3 0

2 years ago

Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibrium described by the equation N2O4(g)

lora16 [44]

Answer: The value of equilibrium constant is 0.997

Explanation:

We are given:

Percent degree of dissociation = 39 %

Degree of dissociation, $\alpha$ = 0.39

Concentration of $N_2O_4$ , c = $\frac{1mol}{1L}=1M$

The given chemical equation follows:

$N_2O_4\rightleftharpoons 2NO_2$

Initial: c -

At Eqllm: $c-c\alpha$ $2c\alpha$

So, equilibrium concentration of $N_2O_4=c-c\alpha =[1-(1\times 0.39)]=0.61M$

Equilibrium concentration of $NO_2=2c\alpha =[2\times 1\times 0.39]=0.78M$

The expression of $K_{c}$ for above equation follows:

$K_{c}=\frac{[NO_2]^2}{[N_2O_4]}$

Putting values in above equation, we get:

$K_{c}=\frac{(0.78)^2}{0.61}\\\\K_{c}=0.997$

Hence, the value of equilibrium constant is 0.997

4 0

2 years ago

What is the optimum pH to separate a mixture of lysine, arginine, and cysteine using electrophoresis

belka [17]

Answer:

9.5

Explanation:

Electrophoresis is a separation technique which involves the passage and the use of electric current in separating amino acid mixtures. The positively charged protein moves to the negative electrode while the negatively charged protein moves to the positive electrode which is in accordance to the law of attraction.

Proteins however perform optimally at the right temperature and pH. Studies shows that the optimum pH to separate a mixture of lysine, arginine, and cysteine using the electrophoresis method of separation is around 9.5

4 0

3 years ago