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DiKsa [7]
3 years ago
12

Which three factors are most important in determining the composition of ocean water

Chemistry
2 answers:
AfilCa [17]3 years ago
4 0
First factor: Density of water
This density of water is affected by the level of salt present in it. They are inversely proportional. This means that as the amount of salt in water increases (water becomes more salty), the density of water would decrease

Second factor: Temperature
Temperature affects the composition of water because as temperature increases, the ocean water evaporates and the salt precipitates. Therefore, this factor is essential in determining the rate by which the ocean water evaporates

Third factor: Salinity
This factor helps in determining the amount of salt present in the ocean, i.e, concentration of salt in the water.

Hope this helps :)


worty [1.4K]3 years ago
4 0

The three main factors that help in determining the composition of ocean water are temperature, salinity, and density.  

The temperature helps in determining the rate of evaporation of the sea. Next factor is salinity, it helps in knowing the salty nature of the ocean, and helps in identifying the other essential factor of ocean water, that is, density. The density is one of the most essential factors, as ocean having more salt composition are less dense in comparison to those having less salt.  


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What are three ways invasive species can be introduced into an environment?
Naily [24]

Answer:

A

B

D

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Explanation:

6 0
2 years ago
In a boys hostel, 1206 eggs were bought for breakfast for the students. How many moles of eggs does this represent?
Evgen [1.6K]

Answer:

6.022×1023

Here, it has been asked how many eggs are in one mole of eggs. The eggs represent the unit which can be atom, ion or molecule. So by the definition of mole, 6.022×1023number of eggs are present in one mole of eggs.

8 0
2 years ago
A 55.0 mL aliquot of a 1.50 M solution is diluted to a total volume of 278 mL. A 139 mL portion of that solution is diluted by a
balu736 [363]

Answer:

0.14 M

Explanation:

To determinate the concentration of a new solution, we can use the equation below:

C1xV1 = C2xV2

Where C is the concentration, and V the volume, 1 represents the initial solution, and 2 the final one. So, first, the initial concentration is 1.50 M, the initial volume is 55.0 mL and the final volume is 278 mL

1.50x55.0 = C2x278

C2 = 0.30 M

The portion of 139 mL will be the same concentration because it wasn't diluted or evaporated. The final volume will be the volume of the initial solution plus the volume of water added, V2 = 139 + 155 = 294 mL

Then,

0.30x139 = C2x294

C2 = 0.14 M

4 0
3 years ago
Read 2 more answers
What is the Ka of a 0.0796 M solution of nitrous acid (HNO2) with a pH of 2.95?
Vadim26 [7]

Answer:

Coefficient = 1.58

Exponent = - 5

Explanation:

pH = 2.95

Molar concentration = 0.0796M

Ka = [H+]^2 / [HA]

Ka = [H+]^2 / 0.0796

Therefore ;

[H+] = 10^-2.95

[H+] = 0.0011220 = 1.122 × 10^-3

Ka = [H+] / molar concentration

Ka = [1.122 × 10^-3]^2 / 0.0796

Ka = (1.258884 × 10^-6) / 0.0796

Ka = 15.815 × 10^-6

Ka = 1.58 × 10^-5

Coefficient = 1.58

Exponent = - 5

4 0
4 years ago
What is the mass, in pounds, of 389 mL of a gas that has a density of 1.29 g/L?
devlian [24]

Answer: Mass of gas is 0.001 pounds.

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given : Mass of gas = ?

Density of gas = 1.29g/L

Volume of gas = 389 ml = 0.389 L     (1L=1000ml)

Putting in the values we get:

1.29g/L=\frac{mass}{0.389L}

mass=0.5grams  

mass=0.5\times 0.002lb=0.001lb       (1g =0.002 lb)

Thus the mass of gas is 0.001 pounds.

7 0
3 years ago
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