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Firlakuza [10]
3 years ago
12

A catalyst decreases the activation energy of a particular exothermic reaction by 56 kJ/mol, to 35 kJ/mol. Assuming that the mec

hanism has only one step, and that the products are 78 kJ lower in energy than the reactants, sketch approximate energy-level diagrams for the catalyzed and uncatalyzed reactions. What is the activation energy for the uncatalyzed reverse reaction
Chemistry
1 answer:
-Dominant- [34]3 years ago
5 0

Answer:

Activation energy for the uncatalyzed reverse reaction = 103 kJ/mol

Explanation:

Activation energy decreases from = 56 kj/mol to 35 kj/mol

products = 78 KJ lower in energy than reactants

Activation energy for the uncatalyzed reverse reaction = 103 kJ/mol

attached below are the sketches of approximate energy-level for both catalyzed and uncatalyzed reactions

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A student dissolved 1.805g of a monoacidic weak base in 55mL of water. Calculate the equilibrium pH for the weak monoacidic base
yawa3891 [41]

Answer:

11.39

Explanation:

Given that:

pK_{b}=4.82

K_{b}=10^{-4.82}=1.5136\times 10^{-5}

Given that:

Mass = 1.805 g

Molar mass = 82.0343 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{1.805\ g}{82.0343\ g/mol}

Moles= 0.022\ moles

Given Volume = 55 mL = 0.055 L ( 1 mL = 0.001 L)

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.022}{0.055}

Concentration = 0.4 M

Consider the ICE take for the dissociation of the base as:

                                  B +   H₂O    ⇄     BH⁺ +        OH⁻

At t=0                        0.4                          -              -

At t =equilibrium     (0.4-x)                        x           x            

The expression for dissociation constant is:

K_{b}=\frac {\left [ BH^{+} \right ]\left [ {OH}^- \right ]}{[B]}

1.5136\times 10^{-5}=\frac {x^2}{0.4-x}

x is very small, so (0.4 - x) ≅ 0.4

Solving for x, we get:

x = 2.4606×10⁻³  M

pOH = -log[OH⁻] = -log(2.4606×10⁻³) = 2.61

<u>pH = 14 - pOH = 14 - 2.61 = 11.39</u>

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3 years ago
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1. How many atoms are there in 2.8 moles of carbon? You must show your work to receive credit.
Zolol [24]

Answer:

The answer to your question is

1.-  1.686 x 10²⁴ atoms

2.- 0.25 moles

Explanation:

1.-

              1 mol ---------------- 6.023 x 10²³ atoms

             2.8 moles ----------  x

              x = (2.8 x 6.023 x 10²³) / 1

              x = 1.686 x 10²⁴ atoms

2.-           1 mol ------------------ 6.023 x 10 ²³ molecules

               x moles -------------  1.50 x 10²³ molecules

              x = (1.50 x 10²³ x 1) / 6.023 x 10²³

              x = 0.25 moles                                                      

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Answer:

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Explanation:

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